$= > ( - 3s + 2t)(4s - t) \\ \\ = > - 3s(4s - t) + 2t(4s - t) \\ \\ = > ( ( - 3s) \times 4s )- (( - 3s) \times t) + (2t \times 4s) - (2t \times t) \\ \\ = > - 12 {s}^{2} - ( - 3st) + 8st - 2 {t}^{2} \\ \\ = > -12 {s}^{2} + 3st + 8st - 2 {t}^{2} \\ \\ = > - 12 {s}^{2} + 11st - 2 {t}^{2}$

7 0

3 years ago

If you help me you get a lot of points

Mrac [35]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

If one of the roots of the equation x² – 4x + k = 0 exceeds the other by 2, then find the roots and determine the value of k.

Verizon [17]

Step-by-step explanation:

the solutions for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -4

c = k

x = (4 ± sqrt(16 - 4k))/2 = 2 ± sqrt(4 - k)

x1 = 2 + sqrt(4 - k)

x2 = 2 - sqrt (4 - k)

x1 = 2 + x2

2 + sqrt(4 - k) = 2 + 2 - sqrt(4 - k)

2×sqrt(4 - k) = 2

sqrt(4 - k) = 1

4 - k = 1

k = 4 - 1 = 3

x1 = 3

x2 = 1

3 0

2 years ago

Read 2 more answers

Explanation 100% needed please

Varvara68 [4.7K]

Answer:

IS WHAT

Step-by-step explanation:

7 0

3 years ago

One step equation x - 17 = 10​

One step equation x - 17 = 10