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horsena [70]
3 years ago
7

What is the product?

Mathematics
1 answer:
Alona [7]3 years ago
7 0

Answer:

\boxed{- 12 {s}^{2}  + 11st - 2 {t}^{2} }

Step-by-step explanation:

=  > ( - 3s + 2t)(4s - t) \\  \\  =  >  - 3s(4s - t) + 2t(4s - t) \\  \\  =  >  ( ( - 3s) \times 4s )- (( - 3s) \times t) + (2t \times 4s) - (2t \times t) \\  \\  =  >  - 12 {s}^{2}  - ( - 3st) + 8st - 2 {t}^{2}  \\  \\  =  >  -12 {s}^{2}  + 3st + 8st - 2 {t}^{2}  \\  \\  =  >  - 12 {s}^{2}  + 11st - 2 {t}^{2}

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