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Dmitry_Shevchenko [17]
3 years ago
14

Five tickets are selected at random, and those five people win a gift card. If 231 tickets were purchased for the fundraiser, ho

w many different groups of winners can there be?
Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

46.2

Step-by-step explanation:

If you divide 231 by 5 then you get that answer.

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I WILL GIVE BRAINLIEST!!!
Basile [38]
I have returned!

36 can technically be either A or B, although A works better. The workers are trying to see which type of vegetables sell better, and it’s easier to see which bar is taller rather than which slice is bigger.

37 would be the median, or the middle of all the values. The median is 30 (two smaller and two bigger values), while the range is 27 (32-5, range of values), the mode is 5 (the value that occurs the most), and the mean is 20.6 (average of all values). The median is the only value larger than 30, so this would be the best one to tell his parents.
5 0
3 years ago
-2x - 5y = 13 2x - 5y =17
Flura [38]

{-2x-5y=13

<u>{2x-5y=17    </u>(+)

<em />  -2x+2x-5y-5y=13+17

-10y=30     /:(-10)

y=-3

2x-5y=17

2x-5*(-3)=17

2x+15=17

2x=2

x=1

<em>Solution: (1; -3)</em>       

6 0
3 years ago
Sara buys soil from a gardener to fill a planter.The gardener has 1.5 cubic feet of soil to sell for $6. Sara buys just enough s
Travka [436]
The first thing you should do is calculate the volume of the prism.
 We have then:
 V = h * L ^ 2
 Where,
 L: side of the square base.
 h: height.
 Substituting we have:
 V = (0.5) * (1) ^ 2 = 0.5 feet ^ 3.
 Then, we can make the following rule of three:
 1.5 feet ^ 3 ---> 6
 0.5 feet ^ 3 ---> x
 Clearing x we have:
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 Answer:
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5 0
3 years ago
I need help with this page
Alika [10]
This is all I can do for now, I might be back to solve the rest, I’m sorry.

3 0
1 year ago
When two of the three numbers are added at a time, the possible sums are 32, 39, 23. What is the sum of all three numbers?
arsen [322]

Answer:

47

Step-by-step explanation:

Let a, b, and c be those three numbers.

When two of the three numbers are added at a time, the possible sums are 32, 39, 23. Let

a+b=32\\ \\a+c=39\\ \\b+c=23

Add these three equations:

a+b+a+c+b+c=32+39+23\\ \\2a+2b+2c=94

Divide this equation by 2:

a+b+c=47

The sum of all three numbers is 47.

4 0
3 years ago
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