Is the expression below a perfect square trinomial or the difference of two squares?

Mathematics

1 answer:

DanielleElmas [232]1 year ago

7 0

The expression shown below is a difference of two squares.

<h3>Is a given expression a perfect square trinomial or a difference of two squares?</h3>

In this problem we have an algebraic expression that has to be checked by algebraic procedures. The complete procedure is shown below:

(x² + 8 · x + 16) · (x² - 8 · x + 16) Given

(x + 4)² · (x - 4)² Perfect square trinomial

[(x + 4) · (x - 4)] · [(x + 4) · (x - 4)] Definition of power / Associative and commutative property

(x² - 16)² Difference of squares / Definition of power / Result

The expression shown below is a difference of two squares.

To learn more on differences of squares: brainly.com/question/11801811

#SPJ1

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cluponka [151]

The answer is A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer: {x = 1/2, y = 1/3

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Step-by-step explanation:

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Paha777 [63]

$Slope\,\,1=\frac{-1}{slope\,\,2}$

So, Both lines are perpendicular

Step-by-step explanation:

We need to identify if lines:

Line 1: (8,12)(7,-5)

Line 2: (-9,3)(8,2)

are parallel, perpendicular, or neither?

Lines are parallel if they have same slopes i.e slope 1= slope2
Lines are perpendicular if their slopes are negative inverses of each other i.e slope 1= -1/slope 2

The formula used to find slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}$