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1 year ago

Is the expression below a perfect square trinomial or the difference of two squares?

Mathematics

1 answer:

DanielleElmas [232]1 year ago

7 0

The expression shown below is a difference of two squares.

<h3>Is a given expression a perfect square trinomial or a difference of two squares?</h3>

In this problem we have an algebraic expression that has to be checked by algebraic procedures. The complete procedure is shown below:

(x² + 8 · x + 16) · (x² - 8 · x + 16) Given

(x + 4)² · (x - 4)² Perfect square trinomial

[(x + 4) · (x - 4)] · [(x + 4) · (x - 4)] Definition of power / Associative and commutative property

(x² - 16)² Difference of squares / Definition of power / Result

The expression shown below is a difference of two squares.

To learn more on differences of squares: brainly.com/question/11801811

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Please help now asap

rusak2 [61]

Answer:

(4 ,26)

Step-by-step explanation:

Try to locate the intersection point of the graph of f and the graph of g

which the point with coordinates (4 , 26)

3 0

3 years ago

Read 2 more answers

Whats the answer please help

lbvjy [14]

The answer would be 6.

8 0

3 years ago

In a children’s book, the mean word length is 3.6 letters with a standard deviation of 2.1 letters. In a novel aimed at teenager

Snowcat [4.5K]

Answer:

Find the mean of the sampling distribution of xC-xT

Calculate and interpret the standard deviation of the sampling distribution. Verify that the 10% condition is met.

Justify that the shape of the sampling distribution

Step-by-step explanation:

2.4 letters. Both distributions of word length are unimodal and skewed to the right. Independent random samples of 40 words

3 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Sally went to the clearance rack at a department store and found a shirt she wanted to buy. The shirt was $36.00 and is on sale

jeka57 [31]

Answer:

33.34%.

Step-by-step explanation:

Given that,

The actual price of the shirt = $36

Price on sale = $24

We need to find the percent of the decrease. The formula for the percentage is given by :

$\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100$

Putting all the values,

$\%=\dfrac{24-36}{36}\times 100\\\\=33.34\%$

So, the percentage decrease in the price of the shirt is 33.34%.

6 0

3 years ago