Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
4 2/3 lbs = small puppy weight
4 2/3 times the small puppies weight = large puppy weight
4 2/3 × 4 2/3 or 4 2/3^2 = 21.77777.... or in mixed number is 21 7/9 lbs
Answer:
Angle ABE = 58
Step-by-step explanation:
This would fulfill the AAA theorem, or 3 angles needing to be congruent. We got 58 by subtracting 89 and 62 from 180, then multiplying that answer by 2 (because it occupies both triangles).
