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3 years ago

Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.

Mathematics

1 answer:

VladimirAG [237]3 years ago

8 0

Answer:

The answer should be 3 :)

Step-by-step explanation:

Pick a point on f(x) and count up until you hit the g(x) point :)

When i did this, i got 3 :)

Have an amazing day!!

Please rate and mark brainliest!!

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Area for rectangle = B*H

Area for triangle = B*H/2

total area = area of triangle + area of rectangle

A of rectangle = 17 * 22 = 374 cm²

Triangle height is not giving so we take 22-10 = 12 cm for the height so

A of triangle = 12*19/2 = 114 cm²

total A = 114 + 374 = 488 cm²

Step-by-step explanation:

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3 years ago

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Pipe A can fill a tank in 5 hours. Pipe B can fill it in 2 hours less time than it takes pipe C, a draining pipe, to empty the t

sukhopar [10]

Answer: Time taken by pipe C to empty the tank = 5 hours.

Step-by-step explanation:

Pipe A can fill a tank in 5 hours.

Let time taken by Pipe C = x ( hours)

Time taken by Pipe B = x-2 ( hours)

Now, with all 3 pipes open, it takes 3 hours to fill the tank, it can be represented as

$\dfrac15+\dfrac1{x-2}-\dfrac1x=\dfrac 13\\\\\Rightarrow\ \dfrac{x-(x-2)}{x(x-2)}=\dfrac13-\dfrac15\\\\\Rightarrow\ \dfrac{x-x+2}{x^2-2x}=\dfrac{5-3}{15}\\\\\Rightarrow \dfrac{2}{x^2-2x}=\dfrac2{15}\\\\\Rightarrow\ x^2-2x=15\\\\\Rightarrow\ x^2-2x-15=0\\\\\Rightarrrow\ x^2-5x+3x-15=0\\\\\Rightarrow\ x(x-5)+3(x-5)=0\\\\\Rightarrow\ (x-5)(x+3)=0\\\\\Rightarrow\ x=5, -3$

Time cannot be negative,

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3 years ago

A factory is to be built on a lot measuring 210 ft by 280 ft. A local building code specifies that a lawn of uniform width and e

Tresset [83]

Answer:

Width of lawn = 35 ft

Dimensions of factory = length: 210 ft, width: 140 ft

Step-by-step explanation:

The total area of the lot can be calculated as:

$A_{lot} = 210 * 280\\A_{lot} = 58800 ft^{2}$

Since, the area of factory should be equal to area of lawn:

$A_{lot} = A_{factory} + A_{lawn}\\58800 = 2 A_{factory or lawn}\\\\A_{factory or lawn} = \frac{58800}{2}\\A_{factory or lawn} = 29400 ft^{2}$

Now, let 'x' be the width of lawn, the dimensions of factory can be written as:

$(210-2x)\\(280-2x)\\$

Since, area is equal to length x width:

$(210-2x)*(280-2x) = 29400\\Simplifying:\\210*280 - 210*2x - 2x*280 + 4x^{2} = 29400\\58800 - 420x - 560x +4x^{2} = 29400\\4x^{2} - 980x +58800 = 29400\\4x^{2} - 980x + 29400 = 0\\$