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bixtya [17]
1 year ago
13

If sin A = 4/5 and A is in quadrant II, find tan 2A.​

Mathematics
1 answer:
ra1l [238]1 year ago
7 0

The value of tan2A given the trig expression is -128/21

<h3>Double angles</h3>

According to the double angle formula

tan 2A = 2tanA/1-tan²A

Given the following

sinA = 4/5 = opp/hyp

Tangent = 3units

TanA = opp/adj

TanA = 4/3

Substitute

Tan2A = 2(4/3)/1-(4/3)²

Tan2A = (8/3)/1-(16/9)

Tan2A = 8/3 * -16/7

Tan2A = -128/21

Hence the value of tan2A given the trig expression is -128/21

Learn more on double angle here: brainly.com/question/14691

#SPJ1

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kodGreya [7K]

Answer:

a)  The arithmetic sequence with common difference 2 that has 8 as the first term.

b) The arithmetic sequence of common difference -5 and first term 15.

Step-by-step explanation:

Let's use for example the arithmetic sequence with common difference 2 that has 8 as the first term. Then the first two terms of this sequence are:

8, and (8+2) = 10 Therefore the second term is 10.

Another arithmetic sequence of common difference -5 and first term 15. The firs two terms of this sequence are:

15, and  (15 - 5)  = 10. Therefore again a 10 as second term.

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1) (-7,2)
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8 0
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Which is the solution to (8.5 x 103)(2 x 105) expressed in scientific notation?
kenny6666 [7]

We have been given an expression (8.5\times 10^3)(2\times 10^5). We are asked to find the solution to our given expression expressed as scientific notation.

Let us simplify our given expression.

Using exponent property a^m\cdot a^n=a^{m+n}, we will get:

8.5\times 2\times 10^3\times 10^5

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Now to write our answer in scientific notation, we need our 1st multiple between 1 and 10. So we will rewrite our expression as:

1.7\times 10\times 10^{8}

1.7\times 10^{1+8}

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3 years ago
In imaginary numbers can you multiply two radicals that have negative values under them that do not square to whole numbers
ElenaW [278]
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .

Take, for example, the commonly known "imaginary number":  "i" ;  which represents the "imaginary number" ;  " √-1 " .

Since:  "i = √-1" ; 

Note that:   " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
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