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balandron [24]
3 years ago
11

Solve, 3y(4y−1)−2y(6y−5)=9y−8(3+y)

Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

3y(4y-1)-2y(6y-5)=9y-8(3+y)

12y∧2-3y-12y∧2+10y=9y-24-8y

12y∧2-12y∧2-3y+10y=9y-8y-24

7y=y-24

7y-y=-24

6y=-24

y=-24/6=-4

Step-by-step explanation:

You might be interested in
What value of X makes this equation true?
Studentka2010 [4]

Answer:

The answer is B

Step-by-step explanation:

-53=8x+5

First you would subtract the 5 on both sides then you would end up with

-58=8x

then you would divide both sides by 8 and get 7.25 or 7 1/4

6 0
3 years ago
Read 2 more answers
Is 9.55x10 to the 3rd power greater than less than or equal to 5,900
erastovalidia [21]

Answer:

See below.

Step-by-step explanation:

9.55 * 10^3 = 9550.

So it is greater than 5,900.

5 0
3 years ago
Helpp, I need to determine the slope and y-intercept for each group. I need to write an equation for the graph in slope-intercep
jenyasd209 [6]

Answer:

Slope = -2

Y intercept = 4

Equation. y = -2x +5

Step-by-step explanation:

Using points, (1,2) and (3,-2)

Slope = (-2-2)/(3-1) = -4/2 = -2

Y intercept = 4

-2 = (y-3)/(x-1)

-2(x-1) = y-3

-2x +2 = y-3

y = -2x +2 +3

y = -2x +5

4 0
3 years ago
Read 2 more answers
√₂
snow_lady [41]

Answer:

$2000 was invested at 5% and $5000 was invested at 8%.

Step-by-step explanation:

Assuming the interest is simple interest.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned.
  • P = principal invested.
  • r = interest rate (in decimal form).
  • t = time (in years).

Given:

  • Total P = $7000
  • P₁ = principal invested at 5%
  • P₂ = principal invested at 8%
  • Total interest = $500
  • r₁ = 5% = 0.05
  • r₂ = 8% = 0.08
  • t = 1 year

Create two equations from the given information:

\textsf{Equation 1}: \quad \sf P_1+P_2=7000

\textsf{Equation 2}: \quad \sf P_1r_1t+P_2r_2t=I\implies 0.05P_1+0.08P_2=500

Rewrite Equation 1 to make P₁ the subject:

\implies \sf P_1=7000-P_2

Substitute this into Equation 2 and solve for P₂:

\implies \sf 0.05(7000-P_2)+0.08P_2=500

\implies \sf 350-0.05P_2+0.08P_2=500

\implies \sf 0.03P_2=150

\implies \sf P_2=\dfrac{150}{0.03}

\implies \sf P_2=5000

Substitute the found value of P₂ into Equation 1 and solve for P₁:

\implies \sf P_1+5000=7000

\implies \sf P_1=7000-5000

\implies \sf P_1 = 2000

$2000 was invested at 5% and $5000 was invested at 8%.

Learn more about simple interest here:

brainly.com/question/27743947

brainly.com/question/28350785

5 0
1 year ago
What is the slope of a line perpendicular to the line containing the points (4,-7) and (-5,-1)? Express your answer as a common
just olya [345]

Answer:

3/2

Step-by-step explanation:

Slope 1 = (-1+7)/(-5-4) = 6/(-9) = -2/3

Slope 2 perpendicular to Slope 1 :

-1 ÷ -⅔ = 3/2

6 0
3 years ago
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