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balandron [24]
3 years ago
11

Solve, 3y(4y−1)−2y(6y−5)=9y−8(3+y)

Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

3y(4y-1)-2y(6y-5)=9y-8(3+y)

12y∧2-3y-12y∧2+10y=9y-24-8y

12y∧2-12y∧2-3y+10y=9y-8y-24

7y=y-24

7y-y=-24

6y=-24

y=-24/6=-4

Step-by-step explanation:

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