At which angle will the hexagon rotate onto itself

What is the solution to this equation 1/2n^2+18=0

ololo11 [35]

Answer:

n = ±6 .

Step-by-step explanation:

A quadratic equation is given to us and we need to find out the solution of the given equation . The given equation is ,

$\rm\implies -\dfrac{1}{2}n^2+18=0$

Subtracting 18 both sides ,

$\rm\implies -\dfrac{1}{2}n^2 = -18$

Multiplying both sides by -2 ,

$\rm\implies -2\times\dfrac{1}{2}n^2 = -2\times -18$

On simplyfing , we get ,

$\rm\implies n^2= 36$

Putting squareroot both sides ,

$\rm\implies n= \sqrt{36}$

This equals to ,

$\rm\implies \boxed{\quad\blue{\rm n =\pm 6 }}$

Hence the value of n is ±6 .

6 0

3 years ago

Base area: 12.5 m2; height: 1.2 m

Novay_Z [31]

Answer:

Volume = 150 m^2

Step-by-step explanation:

Using Volume formula of prism, we get L*W*H, but since we know the area of the base is L*W, which is 12.5, we multiply 12.5 by 12 to get 150 m^2.

7 0

3 years ago

(1.5 ? 10^2) X (2.0 ? 10^3) Express your answer in scientific notation and standard form.

ludmilkaskok [199]

Answer: 3*10^5 or 300,000 cant remember witch one it is

Step-by-step explanation:

1.5*10^2= 150

2*10^3=2,000

150*2000=300,000

3*10^5

4 0

3 years ago

The ratio of berries to Oranges is 10:1 if there are 25 oranges how many berries would there be

Yuki888 [10]

Answer:

250 berries

Step-by-step explanation:

10 to 1 means 10 times as many berries as oranges

25x10=250

8 0

3 years ago

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.

Leni [432]

Answer:

a)

$g(2.9) \approx -6.6$

$g(3.1) \approx -3.4$

b)

The values are too small since $g''$ is positive for both values of $x$ in. I'm speaking of the $x$ values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on that line.

We want to find the equation of the tangent line of the curve $g$ at the point $(3,-5)$ on $g$ .

So we know $(x_1,y_1)=(3,-5)$ .

To find $m$ , we must calculate the derivative of $g$ at $x=3$ :

$m=g'(3)=(3)^2+7=9+7=16$ .

So the equation of the tangent line to curve $g$ at $(3,-5)$ is:

$y-(-5)=16(x-3)$ .

I'm going to solve this for $y$ .

$y-(-5)=16(x-3)$

$y+5=16(x-3)$

Subtract 5 on both sides:

$y=16(x-3)-5$

What this means is for values $x$ near $x=3$ is that:

$g(x) \approx 16(x-3)-5$ .

Let's evaluate this approximation function for $g(2.9)$ .

$g(2.9) \approx 16(2.9-3)-5$

$g(2.9) \approx 16(-.1)-5$

$g(2.9) \approx -1.6-5$

$g(2.9) \approx -6.6$

Let's evaluate this approximation function for $g(3.1)$ .

$g(3.1) \approx 16(3.1-3)-5$

$g(3.1) \approx 16(.1)-5$

$g(3.1) \approx 1.6-5$

$g(3.1) \approx -3.4$

b) To determine if these are over approximations or under approximations I will require the second derivative.

If $g''$ is positive, then it leads to underestimation (since the curve is concave up at that number).

If $g''$ is negative, then it leads to overestimation (since the curve is concave down at that number).

$g'(x)=x^2+7$

$g''(x)=2x+0$

$g''(x)=2x$

$2x$ is positive for $x>0$ .

$2x$ is negative for $x$ .

That is, $g''(2.9)>0 \text{ and } g''(3.1)>0$ .

So $2x$ is positive for both values of $x$ which means that the values we found in part (a) are underestimations.

6 0

3 years ago