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3 years ago

At which angle will the hexagon rotate onto itself

Mathematics

1 answer:

Nuetrik [128]3 years ago

4 0

B) 180 degrees
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3xy - 15x + y ^ 2 - c In the polynomial above, c is a constant. If the polynomial is divisible by y - 5 , what is the value of c

Natalija [7]

Answer:

Step-by-step explanation:

Synthetic division shows the remainder to be 25-c. In order for that remainder to be zero, the value of c must be 25.

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3 years ago

Which algebraic property could be used to rewrite 4x + 2y as 2y + 4x? (3 points)

MAXImum [283]

Answer:

C = commutative property of Addition

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3 years ago

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Solve the equation -2 = 3x/5 + 1

kirill [66]

$- 2 = \dfrac{3x}{5} + 1 | \times 5 \\ - 10 = 3x + 5 \\ - 3x = 15 | \div ( - 3) \\ x = - 5$

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3 years ago

Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3?

Sedbober [7]

Answer:

(1,1)

Step-by-step explanation:

The choices are not visible, however are unnecessary to solve this problem.

Given y = 3x - 2 and y = -2x + 3

[Set them equal to each other]

3x - 2 = -2x + 3

[Find x]

3x + 2x - 2 = 3

3x + 2x = 5

5x = 5

x = 1

[Plug x = 1 to both equations to check and find y]

y = 3x - 2

y = 3(1) - 2 = 3 - 2 = 1

y = -2x + 3

y = -2(1) + 3 = -2 + 3 = 1

Both are equal to y = 1 when x = 1

The point is then: (1,1)

3 0

3 years ago

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1. The number of rabbits on an island is increasing exponentially.

Zina [86]

Answer:

<em>There are approximately 114 rabbits in the year 10</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^t$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

$50=P_o(1+r)^1$

$50=P_o(1+r)\qquad\qquad[1]$

$72=P_o(1+r)^5\qquad\qquad[2]$

Dividing [2] by [1]:

$\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}$

Solving for r:

$\displaystyle r=\sqrt[4]{\frac{72}{50}}-1$

Calculating:

r=0.095445

From [1], solve for Po:

$\displaystyle P_o=\frac{72}{(1+r)^5}$

$\displaystyle P_o=\frac{72}{(1.095445)^5}$

$P_o=45.64355$

The model can be written now as:

$P=45.64355(1.095445)^t$

In year t=10, the population of rabbits is:

$P=45.64355(1.095445)^{10}$

P = 113.6

$P\approx 114$

There are approximately 114 rabbits in the year 10

5 0

3 years ago