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Dima020 [189]
3 years ago
6

Graph the following quadratic function using transformations​

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0
You start with the basic y=x^2.
That’s the parabola with a vertex at (0,0), opening up, etc.

The transformation aspect is the “+7” portion. This “+7” shifts the entire graph of y=x^2 up by 7 units.
The vertex is now (0,7), it still opens up, etc.

It’s kind of a silly question for your teacher to ask when the graph given only goes up to 6.
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Suppose f(x)=2×+5 find the value of -2f(x+1)
loris [4]
F(x) = 2x + 5 

-----------------------------------
Find f(x + 1) :
-----------------------------------
f(x +1) = 2(x + 1) + 5
f(x +1) = 2x + 2 + 5
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-----------------------------------
Find -2f(x+1):
-----------------------------------
-2(fx+1) = -2(2x + 5)
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----------------------------------------------------------------------
Answer: -2(fx+1) = -4x - 10
----------------------------------------------------------------------
3 0
3 years ago
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