The velocity of the car at various times is given as:
Velocity at 15 seconds = f(15) = 45
Velocity at 22 seconds = f(15) = 66
Velocity at 29 seconds = f(15) = 87
Velocity at 36 seconds = f(15) = 108
We are to find the average rate of change of f(x) from x=15 to x=29, which can be written as:
![\frac{f(29)-f(15)}{29-15} \\ \\ = \frac{87-45}{14} \\ \\ = \frac{42}{14} \\ \\ =3](https://tex.z-dn.net/?f=%20%5Cfrac%7Bf%2829%29-f%2815%29%7D%7B29-15%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Cfrac%7B87-45%7D%7B14%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Cfrac%7B42%7D%7B14%7D%20%5C%5C%20%20%5C%5C%20%0A%3D3%20%20%20)
Therefore, the average rate of change of function from x=15 to x=29 is 3. Since the rate of change of velocity gives us acceleration, so the acceleration of the car between 15 to 29 seconds will be 3 m/s²
Answer:
Answer: -7
Step-by-step explanation:
ok so I am no expert (Actually i am it says it on my profile) but the answer is 69/5555*^ I hope that this helps you and if it was so easy then why can't ya do it buddy! lol jkjkjkjk