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bogdanovich [222]

3 years ago

6

Kevin using 84 fluid ounces of water to make in all purpose cleaner. The directions call for 4 fluid ounces of concentrated soap

for every 3 cups of water. How many fluid ounces of soap should he use? (1 cup = 8 ounces)

1 answer:

nata0808 [166]3 years ago

7 0

He should use 886 fluid ounces of soap.

<u>Step-by-step explanation</u>:

Know that 8 fluid ounces make 1 cup.

Now 24 cups need 32 fluid ounces or, 3 fluid ounces of water need 32 fluid ounces of soap.

Thus, by unitary method,

84 ounces of water need 32 × 84 / 3 ounces of soap.

Thus the answer comes to 886 ounces.

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2 years ago

If a fair coin is tossed 6 times, what is the probability, to the nearest thousandth, of getting exactly 6 tails?

xxTIMURxx [149]

<h2>Answer:</h2>

$\frac{1}{64}$

<h2>Step-by-step explanation:</h2>

$The\ probability\ of\ tails\ per\ flip\ is\ \frac{1}{2}$

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$tails\ is$

$\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{64}$

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3 0

2 years ago

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KiRa [710]

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Step-by-step explanation:

7 0

2 years ago

Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

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now, we can set them equal

$r=0$

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$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

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3 years ago

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nydimaria [60]

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3 years ago