What is the slope of the line passing through the points (3,10)and(1,15)

Mathematics

2 answers:

cestrela7 [59]3 years ago

7 0

Put the (3, 10) above (1, 15). Then take 15-10 and put 5 as the numerator, same with 1-3 and put -2 as the denominator. Slope is -5/2

goldfiish [28.3K]3 years ago

5 0

Y^2-y^1/x^2-x^1
15-10/1-3
slope = -5/2

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$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

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