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3 years ago

What is the slope of the line passing through the points (3,10)and(1,15)

Mathematics

2 answers:

cestrela7 [59]3 years ago

7 0

Put the (3, 10) above (1, 15). Then take 15-10 and put 5 as the numerator, same with 1-3 and put -2 as the denominator. Slope is -5/2

goldfiish [28.3K]3 years ago

5 0

Y^2-y^1/x^2-x^1
15-10/1-3
slope = -5/2

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What is the coefficient of X^2Y^2 in the expansion of (x+y)^4

nata0808 [166]

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Step-by-step explanation:

We want to expand this; (x + y)⁴

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3 years ago

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Step-by-step explanation:

Simplify by combining the real and imaginary parts of each expression.

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4 years ago

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3 years ago

Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r

likoan [24]

The value of q(x) is $2 x+5$

The value of r(x) is $6$

Explanation:

The given expression is $\frac{2 x^{2}+13 x+26}{x+4}$

We need to rewrite the expression in the form of $q(x)+\frac{r(x)}{b(x)}$

Simplifying the expression, we get,

$\frac{2 x^{2}+8 x+5x+26}{x+4}$

Separating the fractions, we have,

$\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}$

$2 x+\frac{5 x+26}{x+4}$ -----------(1)

Now, we shall further simplify the term $\frac{5 x+26}{x+4}$ , we get,

$\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}$

Common out 5 from the numerator, we have,

$\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$

Substituting the value $\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$ in the equation(1), we get,

$2 x+5+\frac{6}{x+1}$

Thus, the expression $\frac{2 x^{2}+13 x+26}{x+4}=2 x+5+\frac{6}{x+1}$ is in the form of $q(x)+\frac{r(x)}{b(x)}$

Hence, we have,

$q(x)=2 x+5$

$r(x)=6$ and

$b(x)=x+4$

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3 years ago