Answer:
The 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Step-by-step explanation:
<u>Step :- (i)</u>
Given sample size 'n' =15
sample of the mean x⁻ = 33.2
The standard deviation of the sample 'S' = 8.3
<u>95% of confidence intervals</u>
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<u>Step:-(ii)</u>
<u>The degrees of freedom γ=n-1 = 15-1=14</u>
The tabulated value t = 1.761 at 0.05 level of significance.
now substitute all possible values, we get
After calculation , we get
(33.2-3.7739 , 33.2+3.7739
(29.4261 ,36.9739)
<u>Conclusion</u>:-
the 95% confidence interval of the true mean.
(29.4261 ,36.9739)
