HELLLLP WILL GET F AND FAIL 5TH GRADE IF INCORRECT!!!!! 15 PTS!!!

A car is 3 times as old as its tires were when it was as old as the tires Are now.

serg [7]

Answer:

Present age of the car = 1.5 years and the tires are 0.5 years old.

Step-by-step explanation:

Let the present age of the car be x years and that of the tires be y years.

x = 3y

x = y + 1

3y = y + 1

2y = 1

y = 0.5.

x = 3*0.5 = 1.5.

8 0

3 years ago

A supplier sold a scanner machine for Rs 41,400 with 15% VAT after allowing 10% discount on it's marked price and gained 20%. By

victus00 [196]

3%

Answer:

Selling price with VAT {15%} = Rs 41400

S.P +15% of S.P =Rs 41400

S.P(1+15%)=Rs 41400

S.P=Rs 41400/1.15

Selling price without VAT =Rs 36000

Again

Discount = 10%

M.P =S.P+ Discount % of M.P

M.P-Discount% of M.P= S.P

M.P(1-Discount%)=Rs 36000

M.P(1-10%)=Rs 36000

M.P=Rs 36000/0.9

Marked Price = Rs 40,000

again

Discount =Discount % of M.P

=10% of 40000

=Rs 4,000

Again

Profit=20%

For 20% profit

Cost price = (S.P*100)/(100+profit%)

=(36000*100)/(100+20)

= Rs 30000

For 24% profit

selling price = (100+profit%)*C.P/100

=(100+24)*30000/100

=Rs 37200

Again

Discount = 40000–37200 = Rs2800

Discount % = discount/M.P*100%

=2,800/40,000* 100 = 7%

Finally

Discount percent to be reduced =10%–7%= 3%

3 0

2 years ago

Find the 96th term of the arithmetic sequence 1, -12, -25, ...1,−12,−25,

IrinaK [193]

Answer:

$a_9_6=-1,234$

Step-by-step explanation:

we know that

The rule to calculate the a_n term in an arithmetic sequence is

$a_n=a_1+d(n-1)$

where

d is the common difference

a_1 is the first term

n is the number of terms

we have

$1,-12,-25,...$

Remember that In an Arithmetic Sequence the difference between one term and the next is a constant. and this constant is called the common difference

so

$a_1=1\\a_2=-12\\a_3=-25$

$d=a_2-a_1=-12-1=-13$

Find the 96th term of the arithmetic sequence

$a_n=a_1+d(n-1)$

we have

$a_1=1\\d=-13\\n=96$

substitute

$a_9_6=1+(-13)(96-1)$

$a_9_6=1+(-13)(95)$

$a_9_6=1-1,235$

$a_9_6=-1,234$

8 0

3 years ago

-6 = n/2 - 10 show work

valina [46]

Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

First, add 10 to both sides

-6 (+10) = n/2 - 10 (+10)

10 - 6 = n/2

4 = n/2

Next, isolate the n. Multiply 2 to both sides

4(2) = n/2(2)

n = 4(2)

n = 8

8 is your answer

hope this helps

5 0

4 years ago

A) explain how you can write and solve equations to find the measure of each angle

Ainat [17]

Answer:

A) For line l = (2x + 8°) + (5x - 10°) = 180° ....... (i)

For line k = (3x + 42°) + (x + 34°) = 180° ....... (ii)

B) In line l, two angles are = 60° and 120°

In line k, two angles are = 120° and 60°

Step-by-step explanation:

Requirement A

To find the measure of each angle, we have to use equation.

According to the graph, line l and k are parallel, therefore, both are straight angle. We know that a straight angle is equal to 180°. Therefore, line l and k are 180°. As both the line are intersected by line j, the lines are separated by two angles. So, the equation for line l is -

(2x + 8°) + (5x - 10°) = 180° ....... (i)

the equation for line k is -

(3x + 42°) + (x + 34°) = 180° ....... (ii)

Requirement B

For line "l "

By solving the equations, we can measure the angles

(2x + 8°) + (5x - 10°) = 180°

or, 2x + 8° + 5x - 10° = 180°

or, 7x - 2° = 180°

or, 7x = 180° + 2°

or, 7x = 182°

or, x = 182° ÷ 7 [Dividing both the sides by 7]

or, x = 26°

Therefore, 2x + 8° = 2 × 26° + 8° = 52° + 8° = 60°

the other angle is = 5x - 10° = 5 × 26° - 10° = 130° - 10° = 120°

For line "k "

(3x + 42°) + (x + 34°) = 180°

or, 3x + 42° + x + 34° = 180°

or, 4x + 76° = 180°

or, 4x = 180° - 76° [Deducting 76° from the both the sides]

or, 4x = 104°

or, x = 104° ÷ 4

Hence, x = 26°

Therefore, 3x + 42° = 3 × 26° + 42° = 78° + 42° = 120°

The other angle is = x + 34° = 26° + 34° = 60°

5 0

3 years ago