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S_A_V [24]
1 year ago
8

The radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder wi

th water. The radius of the cone's base is
5 centimeters, and its height is 10 centimeters.
The number of times one needs to use the completely filled cone to completely fill the cylinder with water is
Mathematics
1 answer:
klasskru [66]1 year ago
8 0

The number of times one needs to use the completely filled cone to completely fill the cylinder with water is <u>24</u>.

In the question, we are given that the radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder with water. The radius of the cone's base is 5 centimeters, and its height is 10 centimeters.

We are asked to find the number of times one needs to use the completely filled cone to completely fill the cylinder with water.

The volume of a cylinder is calculated using the formula, V = πr²h.

The volume of a cone is calculated using the formula, V = (1/3)πr²h.

In both the formulas r is the radius and h is the height.

The volume of the given cylinder using the formula is π(10)²(20) cm³ = 2000π cm³.

The volume of the given cone using the formula is (1/3)π(5)²(10) cm³ = (250/3)π cm².

The number of times one needs to use the completely filled cone to completely fill the cylinder with water =

The volume of the given cylinder/The volume of the given cone,

or, The number of times one needs to use the completely filled cone to completely fill the cylinder with water = {2000π cm³}/{(250/3)π cm²},

or, The number of times one needs to use the completely filled cone to completely fill the cylinder with water = 24.

Thus, the number of times one needs to use the completely filled cone to completely fill the cylinder with water is <u>24</u>.

Learn more about the volume of a cylinder and cone at

brainly.com/question/26263468

#SPJ9

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Answer:

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(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

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Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

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When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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