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S_A_V [24]
1 year ago
8

The radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder wi

th water. The radius of the cone's base is
5 centimeters, and its height is 10 centimeters.
The number of times one needs to use the completely filled cone to completely fill the cylinder with water is
Mathematics
1 answer:
klasskru [66]1 year ago
8 0

The number of times one needs to use the completely filled cone to completely fill the cylinder with water is <u>24</u>.

In the question, we are given that the radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder with water. The radius of the cone's base is 5 centimeters, and its height is 10 centimeters.

We are asked to find the number of times one needs to use the completely filled cone to completely fill the cylinder with water.

The volume of a cylinder is calculated using the formula, V = πr²h.

The volume of a cone is calculated using the formula, V = (1/3)πr²h.

In both the formulas r is the radius and h is the height.

The volume of the given cylinder using the formula is π(10)²(20) cm³ = 2000π cm³.

The volume of the given cone using the formula is (1/3)π(5)²(10) cm³ = (250/3)π cm².

The number of times one needs to use the completely filled cone to completely fill the cylinder with water =

The volume of the given cylinder/The volume of the given cone,

or, The number of times one needs to use the completely filled cone to completely fill the cylinder with water = {2000π cm³}/{(250/3)π cm²},

or, The number of times one needs to use the completely filled cone to completely fill the cylinder with water = 24.

Thus, the number of times one needs to use the completely filled cone to completely fill the cylinder with water is <u>24</u>.

Learn more about the volume of a cylinder and cone at

brainly.com/question/26263468

#SPJ9

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Answer:

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Point M is the midpoint of segment AB.<br> AM=3x+40 and MB=x^2. Find x and AB
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\text{Hello there! :)}

x = 8\\\\AB = 128 \text{ units}

-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-

\text{Since Point M is the midpoint of AB, then:}\\\\AM = MB\\\\

\text{Set the two equations equal to each other:}\\\\3x + 40 = x^{2} \\\\

\text{Move all terms over to one side to simplify more easily:}\\\\0 = x^{2} - 3x - 40

\text{Factor by finding numbers that sum up to -3 and multiply into -40:}\\\\0 = (x - 8)(x + 5)\\\\x = -5, 8

\text{The length of a segment cannot be negative, so choose the positive solution:}\\\\x = 8

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