A parabola $ax^2+bx+c$ contains the points $(-1,0)$, $(0,5)$, and $(5,0)$. Find the value $100a+10b+c$.
1 answer:
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A(x) = 3x + 1
b(x) = √(x-4)
Therefore
This composition of functions is only defined as a real number when x≥0.
Therefore its domain is x = [1,∞]
Answer: [1,∞]
b(x) = √(x-4)
Therefore
This composition of functions is only defined as a real number when x≥0.
Therefore its domain is x = [1,∞]
Answer: [1,∞]