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fenix001 [56]
3 years ago
12

Which of the following exponential functions represents the graph below?

Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

the graph corresponds to function "D"  f(x)=3\,(\frac{1}{5} )^x

Step-by-step explanation:

Since the graph shown corresponds to an exponential "decay" (the function decreases as we move from left to right), the base of the exponent has to be a number smaller than 1 (one). So we examine the only two options that give such (options C and D which have fractions as the base - 1/3 and 1/5 respectively)

From there, we analyze which of the two functions satisfies the crossing of the y-axis at (0,3) which is clearly shown in the graph:

We study both:

function C at x = 0 gives:

f(x)= 5\,(\frac{1}{3})^x\\f(0)=5\,(\frac{1}{3})^0 \\f(0)=5\,(1)\\f(0)=5

while function D at x = 0 gives:

f(x)= 3\,(\frac{1}{5})^x\\f(0)=3\,(\frac{1}{5})^0 \\f(0)=3\,(1)\\f(0)=3

Therefore, the graph corresponds to function "D"

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If y= 1/5 when x=3, find y when x=4, given that y varies directly with x
lisov135 [29]

Answer:

<h2>y =  \frac{4}{15}</h2>

Step-by-step explanation:

To find y when x=4, we must first find the relationship between them

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y varies directly with x is written as

<h3>y  \:  \:  \:  \alpha  \: \:   \: kx</h3>

where k is the constant of proportionality

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when y = 1/5

x = 3

Substitute the values into the above formula and solve

That's

<h3>\frac{1}{5}  = 3k \\ 15k = 1 \\ k =  \frac{1}{15}</h3>

So the formula for the variation is

<h3>y =  \frac{x}{15}</h3>

From the question

when x = 4

<h3>y =  \frac{4}{15}</h3>

Hope this helps you

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