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Zepler [3.9K]
2 years ago
11

determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.17, 14, 11, 8,

Mathematics
1 answer:
MArishka [77]2 years ago
6 0

The common difference of the sequence is -3 and the fifth term is 5

<h3>How to determine the common difference?</h3>

The sequence is given as:

17, 14, 11, 8....

The common difference is

d = T2 - T1

So, we have

d = 14 - 17

Evaluate

d = -3

Hence, the common difference of the sequence is -3

<h3>How to determine the fifth term?</h3>

The fifth term is calculated as:

T5 = a + 4d

Where

a = T1 = 17

d = -3

So, we have:

T5 = 17 - 4 * 3

Evaluate

T5 = 5

Hence, the fifth term is 5

<h3>How to determine the nth term?</h3>

The nth term is calculated as:

Tn = a + (n - 1)d

Hence, the nth term is Tn = a + (n - 1)d

Read more about arithmetic sequence at:

brainly.com/question/6561461

#SPJ1

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1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3

Recall that m\log_b(n)=\log_b(n^m), so

ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

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\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)

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ln(2/3 <em>x</em> ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)

exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)

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2/3 <em>x</em> ¹ʹ³ = exp(3)

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3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)

<em>x</em> ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³

<em>x</em> = 3³/2³ exp(3×3)

<em>x</em> = 27/8 exp(9)

which is the same as

<em>x</em> = 27/8 <em>e</em> ⁹

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