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1 year ago

A(3tx-2b)=c(dx-2) Solve the equation for x

Mathematics

1 answer:

Zepler [3.9K]1 year ago

4 0

Answer:

$\frac{2c-2b}{cd-3t}$

Step-by-step explanation:

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Help me with this question please!

BigorU [14]

Answer:

c = 40d+20

Step-by-step explanation:

He has to pay 20 dollars and that can't multiply so the forty has to multiply and it would have to be by d because c is the total cost

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2 years ago

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the area of a square room can be expressed as 196x12y10z6 square feet . hajime is installing a wallpaper border along the perime

pantera1 [17]

Area for square = s² = 196x¹²y¹⁰z⁶

s = √(196x¹²y¹⁰z⁶)

s = 14x⁶y⁵z³

Perimeter = 4*s = 4*(14x⁶y⁵z³) = 56x⁶y⁵z³

Perimeter = 56x⁶y⁵z³ D

7 0

3 years ago

Select the correct answer.

antoniya [11.8K]

Answer:

Step-by-step explanation:

No solutions

8 0

3 years ago

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What is an equation of the line

kaheart [24]

Answer:

A, y + 3 = 2(x + 2)

Step-by-step explanation:

Point slope form is y -y1 = m(x - x1)

To find the equation for this line, plug in y1, m, and x into the equation.

m = 2

y1 = -3

x1 = -2

y - -3 = 2(x - -2)

Since subtracting a negative changes the sign to a positive, the equation becomes:

y + 3 = 2(x + 2)

This is option A.

3 0

3 years ago

Suppose a large shipment of compact discs contained 19% defectives. If a sample of size 343 is selected, what is the probability

Yuri [45]

Answer:

The value is $P( | \^p - p | < 0.04) = 0.9408$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.19$

The sample size is n = 343

Generally given that the ample size is large enough , i.e n > 30 then the mean of this sampling distribution is mathematically represent

$\mu_{x} = p = 0.19$

Generally the standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{p(1- p)}{n} }$

=> $\sigma =\sqrt{\frac{0.19 (1- 0.19 )}{343 } }$

=> $\sigma = 0.0212$

Generally the the probability that the sample proportion will differ from the population proportion by less than 4% is mathematically represented as

$P( | \^p - p | < 0.04) = P( \frac{|\^ p - p |}{ \sigma_p } < \frac{0.04}{0.0212 } )$

$\frac{|\^ p - p |}{\sigma } = |Z| (The \ standardized \ value\ of \ |\^ p - p | )$

$P( | \^p - p | < 0.04) = P( |Z| < 1.887 )$

=> $P( | \^p - p | < 0.04) = P( Z < 1.887 )- P( Z < -1.887 )$

From the z table the area under the normal curve to the left corresponding to 1.887 and - 1.887 is

$P( Z < 1.887 )= 0.97042$

and

$P( Z < -1.887 )= 0.02958$

$P( | \^p - p | < 0.04) = 0.97042 - 0.02958$

=> $P( | \^p - p | < 0.04) = 0.9408$

3 0

2 years ago