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Naily [24]
3 years ago
9

The length of a rectangle is 2 more than its width. If the area of the rectangle is 20m squared, what are the dimensions of the

rectangle, to the nearest tenth of a metre?
Mathematics
1 answer:
zvonat [6]3 years ago
6 0
L=2+W
A=LW
A=(2+W)W
20=2W+W^2
0=W^2+2W-20
use quadratic
fr
aw^2+bw+C=0
w=(-b+/-sqrt(b^2-4ac))/2a

a=1
b=2
c=-20

w=(-2+/-sqrt(2^2-4(1)(-20)))/2(1)
w=(-2+/-sqrt(4+80))/2
w=(-2+/-sqrt(84))/2
w=(-2+/-2sqrt(21))/2
w=1+/-sqrt(21)
aprox
w=-3.58 or 5.58
cannot have negative width
w=5.58
round
w=5.6
sub
l=2+w
l=2+5.6
l=7.6


legnth=7.6m
width=5.6m
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It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.

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