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Sav [38]
3 years ago
10

If m2=40 what is the m5

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

100

Step-by-step explanation:

Solve for m

2m= 40

Divide both sides 2

m= 20

5(20)= 100

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Alexus [3.1K]
R = ((3V)/((pi)(h^2))+h)/3
6 0
3 years ago
After an earthquake, 1/4 of all claims were paid within a month. Of the remaining claims that had not yet been paid, 4/7
eduard

Answer:

16/28 claims

Step-by-step explanation:

7/28

16/28

- You need to find common denominator. (use 28)

- If you would like a further explanation please let me know.

4 0
3 years ago
I need help with this question
Wittaler [7]

Answer:

A=W, B=X, C=Y, D=Z, AB=WX, BC=XY, CD=YZ, AD=WZ

(The second answer down)

Step-by-step explanation:

3 0
2 years ago
Students were surveyed about their favorite colors 1/4 preferred red, 1/8 preferred blue, 3/5 preferred green. If 15 students pr
const2013 [10]

Answer:

Let us assume the total number of students surveyed = x

Then

Number of students preferring red = x/4

Number of students preferring blue = x/8

Then

Number of students remaining = x - [(x/4) + (x/8)]

                                                  =x - [(2x + x)/8)

                                                  = x - (3x/8)

                                                  = (8x - 3x)/8

                                                  = 5x/8

Number of students preferring the color green = (3/5) * (5x/8)

                                                                          = 3x/8

We also know that the total number of students preferring the color green is 15

So

3x/8 = 15

3x = 15 * 8

x = (15 * 8)/3

  = 5 * 8

  = 40

So in total 40 students were surveyed. I hope the procedure is clear to you.

Step-by-step explanation:

6 0
2 years ago
I need help pls.............
Sever21 [200]

Answer:

  • P = 6750n +7800r
  • n ≤ 19
  • r ≤ 31
  • 160n +620r ≤ 8110
  • n = 19
  • r = 8
  • 190,650 people

Step-by-step explanation:

This linear programming problem is described by an objective function and constraints on the variables. A graphical solution works well.

<h3>Objective function</h3>

The goal is to maximize the number of people exposed to the company's ad(s). The number of people reached is the sum of the products of the number of ads and the number reached per ad.

For n newspaper ads, we are told that 6750n people are reached.

For r radio ads, we are told that 7800r people are reached.

The total number of people reached is ...

  P = 6750n +7800r . . . . . . . the function we wish to maximize

<h3>Newspaper ads</h3>

We can run at most 19 newpaper ads:

  n ≤ 19

<h3>Radio ads</h3>

We can run at most 31 radio ads:

  r ≤ 31

<h3>Budget</h3>

The cost of n newspaper ads will be $160n.

The cost of r radio ads will be $620r.

We must stay within a budget for the ads, $8100:

  160n +620r ≤ 8110

<h3>Solution</h3>

The white area in the first quadrant of the attached graph represents the feasible solution space. (We reversed the inequality symbol in each inequality so the solution space would be white, not triple-shaded.) The corners of the solution space represent possible (n, r) pairs where the objective function might be maximized.

The solid red line on the graph shows the maximum value the objective function might have, and the (n, r) pairs that would give that maximum value. The value of the objective function increases the farther the line is from the origin. Drawing the line on the graph lets us readily identify the (n, r) coordinate pair that will place this line as far as possible from the origin, maximizing P. We find that to be (n, r) = (19, 8).

  • the number of newspaper ads to run is 19
  • the number of radio ads to run is 8
  • the group exposure is (6750)(19) +(7800)(8) = 190,650

3 0
1 year ago
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