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Ket [755]
1 year ago
13

A shipment of 10 computers contains 2 with defects. Find the probability that a sample of size 2​, drawn from the ​10, will not

contain a defective computer.

Mathematics
1 answer:
Mrrafil [7]1 year ago
8 0

Answer:

\frac{28}{45} .

Step-by-step explanation:

way_1:

according to the condition the probability for the 1st computer is 8/10=4/5;

for the 2d computer is 7/9. Then the final probability is P=4/5 * 7/9=28/45;

way_2:

the required probability can be calculated according the formula:

P=\frac{no-cases}{total-cases};

then

P=\frac{C^2_8}{C^2_{10}} =\frac{2!8!8!}{2!6!10!}=\frac{28}{45} .

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