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3 years ago

15

X^2+3x-24= x 2 +3x−24= \,\,3x+1 3x+1

1 answer:

Vika [28.1K]3 years ago

6 0

Answer:

x=8 lol this is so easyndiewkkwwkwkwkw

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Given that f(x) = 6x - 5 g(x) = 3x + 4 and h(x) = 4x – 6

bazaltina [42]

Answer:

(i) $g(-2)=-2$

(ii) $g[h(x)]=12x-14$

(iii) $f[g(2)]=55$

(iv) $(g\circ h)(2)=10$

(v) $h^{-1}(11)=\frac{17}{4}$

Step-by-step explanation:

The given functions are

$f(x)=6x-5$

$g(x)=3x+4$

$h(x)=4x-6$

(i) Find g(-2).

Substitute x=-2 in g(x).

$g(-2)=3(-2)+4\Rightarrow -6+4=-2$

(ii) Find g[h(x)]

$g[h(x)]=g(4x-6)$ $(h(x)=4x-6)$

$g[h(x)]=3(4x-6)+4$ $(g(x)=3x+4)$

$g[h(x)]=12x-18+4$

$g[h(x)]=12x-14$

(iii) Find f[g(2)].

$f[g(2)]=f[3(2)+4]$ $(g(x)=3x+4)$

$f[g(2)]=f(6+4)$

$f[g(2)]=f(10)$

$f[g(2)]=6(10)-5$ $f(x)=6x-5$

$f[g(2)]=55$

iv) Find gᴏh(2).

$(g\circ h)(2)=g[h(2)]$

$(g\circ h)(2)=12(2)-14$ (From part (ii) we get $g[h(x)]=12x-14)$

$(g\circ h)(2)=10$

(v) Find $h^{-1}(11)$

First find $h^{-1}(x)$ .

$h(x)=4x-6$

$y=4x-6$

$x=4y-6$

$x+6=4y$

Divide both sides by 4.

$\frac{x+6}{4}=y$

$h^{-1}(x)=\frac{x+6}{4}$

Substitute x=11 in the inverse function.

$h^{-1}(11)=\frac{11+6}{4}$

$h^{-1}(11)=\frac{17}{4}$

6 0

4 years ago

I can't seem to figure out the answer to #10. Any help? (Ignore my work)

sashaice [31]

First I think you need to find the angle of the sector. Since it is one hour, and a clock has 12 hours, you would divide 360 by 12 to get 30. then you would do this:
(30/360)(2)(pi)(16)
you would get 8.37758041

8 0

4 years ago

In the figure, lines m and n are parallel to each other. Lines p and q are also parallel to each other. What is the value of x?

Nata [24]

Answer:

C) 100°

Step-by-step explanation:

the angles are actually alternate exterior angles, which means that they're equal.

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%7B4%7D%5E%7B2%7D%20%20-%204%284%29%283%29" id="TexFormula1" title=" {4}^{2} - 4(4)(3)" al

boyakko [2]

The answer to this problem is -32

6 0

3 years ago

What is the quotient of 15a^4b^3/12a^2b? assume that the denominator does not equal zero

Darina [25.2K]

Answer:

$→\frac{15 {a}^{4} {b}^{3}}{12 {a}^{2}b} = \frac{5 {a}^{2} {b}^{2}}{4}✓ \\$

<h3><u>(</u><u>5/4</u><u>)</u><u>a²b²</u> is the right answer.</h3>

3 0

3 years ago