Answer:
The molarity of the solution is 1, 23 M.
Explanation:
We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)
Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g
58, 5 g-----1 mol NaCl
89,94 g ---------x= (89,94 g x 1 mol NaCl)/58, 5 g= 1,54 mol NaCl
1249 ml solution------ 1,54 mol NaCl
1000ml solution------x= (1000ml solutionx 1,54 mol NaCl)/1249 ml solution
x=1,23 mol NaCl---> The solution is 1, 23 molar (1,23 M)
