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mote1985 [20]
2 years ago
12

A sample of water with a mass of 648.00 kg at 298 k is heated with 87 kj of energy. the specific heat of water is 1 j-1 kg k-1.

what is the final temperature of the water?
Mathematics
1 answer:
9966 [12]2 years ago
4 0

The final temperature of the water is 298. 14 k

<h3>What is quantity of heat?</h3>

The formula for quantity of heat is given as:

Q = mc Δ T = m c ( final temperature - initial temperature)

Where:

  • Q is Heat supply = 87 kj
  • m is the mass of substance = 648.00 kg
  • c is the specific heat capacity = 1 j-1 kg k-1
  • ΔT is the temperature change

Substitute the values

87 = 648 × 1 ( T₂ - 298)

87 = 648 ( T₂ - 298)

Divide both sides by 648

87/ 648 = ( T₂ - 298)

0. 134 =  T₂ - 298

Make 'T₂' subject of formula

T₂ = 298 + 0. 134

T ₂ = 298. 14 k

Thus, the final temperature of the water is 298. 14 k

Learn more about quantity of heat here:

brainly.com/question/490326

#SPJ1

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