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Alexxx [7]
3 years ago
11

A rectangle has length 4 inches and width 3 inches. What is the area? 100pts

Mathematics
2 answers:
aliya0001 [1]3 years ago
7 0

Answer:

12 sq in

Step-by-step explanation:

L=4 in

W=3 in

Formula for Area is length x width (or bxh)

So, l x w = 4 x 3 = 12 sq in (in^2)

Ugo [173]3 years ago
5 0

Answer:

12 inches²

Step-by-step explanation:

Area of rectangle = Length × Width

Length = 4 in

Width = 3 in

Area = 4 × 3

Area = 12 in

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Type the correct answer in each box.<br><br> The value of x is °, and the value of y is <br> °.
Solnce55 [7]

Answer:

<h2>x = 60°, y = 50°</h2>

Step-by-step explanation:

We know: the angles measures in a triangle add up to 180°.

<em>(look at the picture)</em>

z + 50 + 60 = 180

z + 110 = 180    <em>subtract 110 from both sides</em>

z = 70°

x + 50 + 70 = 180

x + 120 = 180         <em>subtract 120 from both sides</em>

x = 60°

Angles x, y and z are on one side of a straight line. Therefore they add to 180°.

x + y + z = 180

60 + y + 70 = 180

y + 130 = 180         <em>subtract 130 from both sides</em>

y = 50°

4 0
3 years ago
The algebra symbol f(n) means what?
JulijaS [17]

Answer:

it means y

its just another way of saying it

8 0
3 years ago
Read 2 more answers
Write the ratio in simplest form:<br> 36 to 78
Marysya12 [62]

Answer:

18 : 39

Step-by-step explanation:

36 to 78

Divide both sides by 2.

=> 18 : 39

8 0
2 years ago
Read 2 more answers
What is the product? 6(x*2-1)(6x-1/6(x+1))
Yanka [14]
6(x^2-1)(6x-1/6(x+1))

On factoring (x^2-1)=(x+1)(x-1)

= 6(x-1)(x+1)(6x-1/6(x+1))
Cancelling (x+1) from numerator and denominator we get,

= 6(x-1)(6x-1)/6

Cancelling 6 we get,
= (x-1)(6x-1)
4 0
3 years ago
Graph the system of equations on graph paper.
erastova [34]

If these are the missing choices:

<span>The ordered pair that is the solution to the system lies in Quadrant I . 
The ordered pair that is the solution to the system lies in Quadrant II . 
The x-coordinate of the solution is −3 . 
The y-coordinate of the solution is 3. 
The x-coordinate of the solution is 3. 
The y-coordinate of the solution is 4. </span>

 

Given:

<span>1st equation: 8x + 6y = 48
2nd equation: 2x - 3y = -6</span>

<span>My solution:</span>

<span>We need to zero out one variable to get the value of the other. In this case, we need to multiply the 2nd equation by 4 to zero out variable x.</span>

<span>4(2x – 3y) = 4(-6)</span>

8x – 3y = -24

 

<span>We then subtract the answer of the 2nd equation from the 1st equation.</span>

 

8x + 6y = 48

-(8x -3y = -24)

 

8x + 6y = 48

<u>-8x + 12y = + 24</u>

<span>  0 + 18y = 72</span>

y = 72 / 18

y = 4

 

<span>We then substitute y by its value in the 1st equation to get the value of x.</span>

8x + 6(4) = 48

8x + 24 = 48

8x = 48 – 24

8x = 24

x = 24/8

x = 3

 

the coordinate point is (3,4).

<span>Of the 6 choices, the following choices are TRUE:</span>

<span>The ordered pair that is the solution to the system lies in Quadrant I . 
The x-coordinate of the solution is 3. 
The y-coordinate of the solution is 4. </span>

 

<span> </span>

3 0
3 years ago
Read 2 more answers
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