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Aleksandr [31]
3 years ago
9

4n+12=4 how to slove tow step equations​

Mathematics
2 answers:
julsineya [31]3 years ago
8 0
4n=4-12
4n=-8
n=-2
!!!!!!!!!!!
natulia [17]3 years ago
6 0

Answer:

n=-2

Step-by-step explanation:

4n+12=4

Minus 12 from both sides

4n=-8

Divide both sides by 4

n=-2

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There are 102102 students in a statistics class. The instructor must choose two students at random. Students in a Statistics Cla
asambeis [7]

Answer:

0.0087 probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

What is the probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random?

There are 5 freshman non-Statistics majors out of 102 students.

Then, there will be 18 junior statistics majors out of 101 students(1 will have already been chosen). So

p = \frac{5}{102}*\frac{18}{101} = \frac{5*18}{102*101} = 0.0087

0.0087 probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random

8 0
3 years ago
Sally makes a fruit drink using ⅔ of a cup of orange juice for every ¼ of a cup of pineapple juice. How many cups of orange juic
Shkiper50 [21]

Answer:

5 1/3

Step-by-step explanation:

Set up ratio.

2/3 cup orange juice    X    2 cups  pineapple juice

———————————-

1/4 cup pineapple juice

first multiply numerator :  2/3 x 2   =  4/3

and divide by denominator

(4/3)/(1/4). Keep the first.  Change the sign to multiplication and Flip the second fraction.

4/3 x 4/1 = 16/3

change to proper fraction :  16/3 = 5 1/3 cups

7 0
3 years ago
Ryan has 3 times as many nickels as dimes. The coins have a total of $1.50. How many of each coin foes he have?​
mafiozo [28]
0.5?maybe I just divided 1.50 by 3
5 0
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Read 2 more answers
What is the slope of the line through the given points:
telo118 [61]

Answer: slope is 1

equation: 1x-2 or x-2

I hope this is good enough:

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Dr. Miriam Johnson has been teaching accounting for over 20 years. From her experience, she knows that 60% of her students do ho
oksano4ka [1.4K]

Answer:

a) The probability that a student will do homework regularly and also pass the course = P(H n P) = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P') = 0.12

c) The two events, pass the course and do homework regularly, aren't mutually exclusive. Check Explanation for reasons why.

d) The two events, pass the course and do homework regularly, aren't independent. Check Explanation for reasons why.

Step-by-step explanation:

Let the event that a student does homework regularly be H.

The event that a student passes the course be P.

- 60% of her students do homework regularly

P(H) = 60% = 0.60

- 95% of the students who do their homework regularly generally pass the course

P(P|H) = 95% = 0.95

- She also knows that 85% of her students pass the course.

P(P) = 85% = 0.85

a) The probability that a student will do homework regularly and also pass the course = P(H n P)

The conditional probability of A occurring given that B has occurred, P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

And we can write that

P(A n B) = P(A|B) × P(B)

Hence,

P(H n P) = P(P n H) = P(P|H) × P(H) = 0.95 × 0.60 = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P')

From Sets Theory,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

P(H n P) = 0.57 (from (a))

Note also that

P(H) = P(H n P') + P(H n P) (since the events P and P' are mutually exclusive)

0.60 = P(H n P') + 0.57

P(H n P') = 0.60 - 0.57

Also

P(P) = P(H' n P) + P(H n P) (since the events H and H' are mutually exclusive)

0.85 = P(H' n P) + 0.57

P(H' n P) = 0.85 - 0.57 = 0.28

So,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

Becomes

0.03 + 0.28 + 0.57 + P(H' n P') = 1

P(H' n P') = 1 - 0.03 - 0.57 - 0.28 = 0.12

c) Are the events "pass the course" and "do homework regularly" mutually exclusive? Explain.

Two events are said to be mutually exclusive if the two events cannot take place at the same time. The mathematical statement used to confirm the mutual exclusivity of two events A and B is that if A and B are mutually exclusive,

P(A n B) = 0.

But, P(H n P) has been calculated to be 0.57, P(H n P) = 0.57 ≠ 0.

Hence, the two events aren't mutually exclusive.

d. Are the events "pass the course" and "do homework regularly" independent? Explain

Two events are said to be independent of the probabilty of one occurring dowant depend on the probability of the other one occurring. It sis proven mathematically that two events A and B are independent when

P(A|B) = P(A)

P(B|A) = P(B)

P(A n B) = P(A) × P(B)

To check if the events pass the course and do homework regularly are mutually exclusive now.

P(P|H) = 0.95

P(P) = 0.85

P(H|P) = P(P n H) ÷ P(P) = 0.57 ÷ 0.85 = 0.671

P(H) = 0.60

P(H n P) = P(P n H)

P(P|H) = 0.95 ≠ 0.85 = P(P)

P(H|P) = 0.671 ≠ 0.60 = P(H)

P(P)×P(H) = 0.85 × 0.60 = 0.51 ≠ 0.57 = P(P n H)

None of the conditions is satisfied, hence, we can conclude that the two events are not independent.

Hope this Helps!!!

7 0
3 years ago
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