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3 years ago

Find the area of the parallelogram shown below.

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

<h2>120 square units </h2>

Step-by-step explanation:

Given, 

Base of the parallelogram = 10

Height of the parallelogram = 12

Therefore, 

Area of the parallelogram = base × height 

= 10 × 12

= 120

Hence,

Area of the parallelogram is 120 square units (Ans)

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Expand the following expression (x + 2)(x² – 3x - 1)

Cloud [144]

Answer:

$x^{3} - x^{2} - 7x -2$

Step-by-step explanation:

Give me brainllest

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3 years ago

Read 2 more answers

Each course at a community college is worth 1 or 2 credits. A group of students is taking a total of 16 courses that are worth a

Anuta_ua [19.1K]

Answer:

They are taking 12 2 credit courses

The are taking 4 1 credit courses

Step-by-step explanation:

x = 1 credit courses

y = 2 credit courses

The number of courses is 16

x+y = 16

The number of credits is 28 so multiply the course by the number of credits

1x+2y=28

Subtract the first equation from the second equation

x+2y =28

-x-y=-16

-----------------

y = 12

They are taking 12 2 credit courses

We still need to find the 1 credit courses

x+y = 16

x+12= 16

Subtract 12 from each side

x-12-12 = 16-12

x =4

The are taking 4 1 credit courses

6 0

2 years ago

g A trial jury of 6 people is selected from 20 people: 8 women and 12 men. What is the probability that the jury will have an od

cricket20 [7]

Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

Number of men = 12

Number of women = 8

Number of jury to be selected = 6

For the jury to have an odd number of women. it must have either of the three.

1. 1 woman , 5 men

2. 3 women, 3 men

3. 5 women, 1 man

The total possible ways of selecting the 6 people jury is;

N = 20C6 = 20!/6!(20-6)!

N = 38760

The possible ways of selecting;

Case 1 : 1 woman, 5 men

N1 = 8C1 × 12C5

N1 = 8 × 792 = 6336

Case 2 : 3 women , 3 men

N2 = 8C3 × 12C3

N2 = 12320

Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

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3 years ago

Where can the bisectors of the angles of an obtuse triangle intersect

Sliva [168]

That point of concurrency is called the incenter of the triangle

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3 years ago

Which phrase represents the algebraic expression StartFraction 3 p + 6 Over 7 p minus 9 End Fraction?

Anarel [89]

Answer:

Step-by-step explanation:

(3p+6)/(7p-9)

4 0

2 years ago