Answer:
PART ONE
- import java.util.Scanner;
- public class CountToLimit {
- public static void main(String[] args) {
- Scanner scnr = new Scanner(System.in);
- int countLimit = 0;
- int printVal = 0;
- // Get user input
- System.out.println("Enter Count Limit");
- countLimit = scnr.nextInt();
- do {
- System.out.print(printVal + " ");
- printVal = printVal + 1;
- } while ( printVal<=countLimit );
- System.out.println("");
- return;
- }
- }
PART TWO
- import java.util.Scanner;
- public class NumberPrompt {
- public static void main (String [] args) {
- Scanner scnr = new Scanner(System.in);
- System.out.print("Your number < 100: ");
- int userInput = scnr.nextInt();
- do {
- System.out.print("Your number < 100: ");
- userInput = scnr.nextInt();
- }while (userInput>=100);
- System.out.println("Your number < 100 is: " + userInput);
- return;
- }
- }
Explanation:
In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14
In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10
Answer:
Hi,
The best option in the list is <u>stop posting her e-mail address on newsgroups.</u>
Explanation:
Unwanted e-mail is categorized as a spam email.These emails can not be entirely avoided because we use the Internet thus it is recommended that you filter them.A program called my email client can help to filter spam though in some cases, it might not be effective.
The techniques Nadia can employ in this case is to hidden her email address when visiting newsgroups.News groups are forums online where people discuss certain topic.Avoid publishing the email in these web sites can hide her tackle this problem. Additionally, Nadia could train the filter serach feature in her email box through repoting such emails using the report button present, avoid responding/openning spam or use a third party program to track spam emails and block them.
Wish you Luck!
Answer:
Ada Lovelace was the first computer programmer
A. defragging your hard drive
Answer:
115200000 bits
Explanation:
Given Data:
Total Time = 3 minute = 3 x 60 sec = 180 sec
Sampling rate = 40,000 bits / sample
Each sample contain bits = 16 bits /sample
Total bits of song = ?
Solution
Total bits of song = Total Time x Sampling rate x Each sample contain bits
= 180 sec x 40,000 bits / sec x 16 bits /sample
= 115200000 bits
= 115200000/8 bits
= 14400000 bytes
= 144 MB
There are total samples in one second are 40000. Total time of the song is 180 seconds and one sample contains 16 bits. so the total bits in the song are 144 MB.
