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jeka94
1 year ago
10

The y-coordinated is zero and the x-coordinate is negative. Is the point in Quadrant II? Explain​

Mathematics
1 answer:
I am Lyosha [343]1 year ago
3 0

Question 19

Answer: No, it is not in quadrant 3.

Explanation:

In order to be in quadrant 3, we need two things

x must be negative

y must be negative

An example point in the third quadrant is (-9, -12).

Both (x,y) coordinates must be negative to be located in quadrant 3. This is the southwest quadrant on the xy grid. We're told that x = 0 which means we are not in quadrant 3. Points on the x or y axis are not part of any quadrant. They are on the boundaries between quadrants (think of it like a fence or a wall).

============================================================

Question 20

Answer: No, it is not in quadrant 2

Explanation:

We use a very similar idea as the previous question. Since y = 0, this point is on a boundary and not in any quadrant. To be in the second quadrant, we need these two conditions to be true:

x must be negative

y must be positive

For example, the point (-5, 7) is in quadrant 2. This quadrant is in the northwest on the xy grid.

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[Hello,BrainlyUser!\; I'm\;Lenvy]

Your\;Answer\;Is\;Below

Answer:

42 feet

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First let know what is

Yards to Feet

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1 Yard ⇒ 3 Feet

Thus, Formula: Multiply the length value by 3

Given:

Lena bought 14 yards of ribbon. How many feet of ribbon did she buy?

Therefore, 14 * 3 = 42

Hence, Answer is Lena brough 42 feet of ribbon.

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marusya05 [52]
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3 years ago
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Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

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3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

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k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

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3 0
2 years ago
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Answer:

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3 0
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padilas [110]
<h3>Answer:   The fraction  2/5</h3>

=========================================================

Explanation:

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with any two points you want from the graph.

4 0
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