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1 year ago

The y-coordinated is zero and the x-coordinate is negative. Is the point in Quadrant II? Explain

Mathematics

1 answer:

I am Lyosha [343]1 year ago

3 0

Question 19

Answer: No, it is not in quadrant 3.

Explanation:

In order to be in quadrant 3, we need two things

x must be negative

y must be negative

An example point in the third quadrant is (-9, -12).

Both (x,y) coordinates must be negative to be located in quadrant 3. This is the southwest quadrant on the xy grid. We're told that x = 0 which means we are not in quadrant 3. Points on the x or y axis are not part of any quadrant. They are on the boundaries between quadrants (think of it like a fence or a wall).

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Question 20

Answer: No, it is not in quadrant 2

Explanation:

We use a very similar idea as the previous question. Since y = 0, this point is on a boundary and not in any quadrant. To be in the second quadrant, we need these two conditions to be true:

x must be negative

y must be positive

For example, the point (-5, 7) is in quadrant 2. This quadrant is in the northwest on the xy grid.

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2 years ago

John is solving x^2 + 4x + 8=0 by completing the square. Which step would be part of John's solution.?

SOVA2 [1]

Answer:

$(x + 2) ^{2} = - 8$

Step-by-step explanation:

${x}^{2} + 4x + 8 = 0 \\ {x }^{2} + 4x = - 8 \\ {x}^{2} + 4x + 4 = - 8 + 4 \\ ( x + 2)^{2} = - 4$

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2 years ago

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

$=(2^5)^\frac{1}{5}$

$=2$

There is no extraneous solution.

3 0

2 years ago

The volume of the polyhedron is ______ yd3.

DochEvi [55]

Answer:

122,850 yd³

Step-by-step explanation:

The polyhedron is a right triangle prism

Area of the right triangle prism = ½*a*c*h

a = 91 yd

c = 60 yd

h = 45 yd

Volume = ½*91*60*45

= 122,850 yd³

4 0

2 years ago

Graph y equals 1/2 x - 3

Elis [28]

Answer:

Resulting plot in the image attached

Step-by-step explanation:

Start by making a table of (x,y) pairs that satisfy this equation. Notice that two pairs would be enough, but it is always safer to obtain at least three to see them actually "aligned".

We are trying to find values for y when x= 0, 2, and 4 to make our calculations simple:

$y=\frac{1}{2} x-3$

When x = 0 then: $y=\frac{1}{2} (0)-3=-3$ So we plot the value (0,-3) on the x-y plane.

When x = 2 then: $y=\frac{1}{2} (2)-3=1-3=-2$ So we plot the value (2,-2) on the x-y plane.

When x = 0 then: $y=\frac{1}{2} (4)-3=2-3=-1$ So we plot the value (4,-1) on the x-y plane.

Please see the points and the resulting line in the image attached

5 0

2 years ago

The y-coordinated is zero and the x-coordinate is negative. Is the point in Quadrant II? Explain​

The y-coordinated is zero and the x-coordinate is negative. Is the point in Quadrant II? Explain