The first step is to find the CHANGE. This is done by subtracting the two values and taking the absolute value. Next step is to find the ratio of the change to the original and multiplying by 100% to make it a percentage.
So;
a) change = Ι60 - 25Ι = 35.
ratio of change to original = 35:25,
multiplying by 100% will give 35/25 × 100% = 140%.
Hence it is a 140% INCREASE.
b) change = | 30 - 66 | = 36
the ratio is 36:66
multiplying by 100% = 36/66 × 100% = 0.545454... ×100% ≈ 54.5%
Hence it is a 54.5% DECREASE.
Helpful?
Answer:
0.0016283
Step-by-step explanation:
Given that:
Proportion of defective bulbs, p = 30% = 0.3
Sample size, n = 19 bulbs
Probability that the lot will pass inspection :
P(none of the 19 is defective) Or P(only one of the 19 is defective)
P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19
0.7^19 = 0.0011398
P(only one of the 19 is defective) :
P(1 defective) * P(18 not defective )
(0.3) * (1 - 0.3)^18
0.3 * 0.7^18
0.3 * 0.001628413597910449 = 0.0004885
Hence,
P(none of the 19 is defective) + P(only one of the 19 is defective)
0.0011398 + 0.0004885) = 0.0016283
Answer:
Your name is the answer to the riddle.
1 Whole is bigger than a fraction
1 part of the 6 equal groups is shaded
1/3
Answer:
In assumption, x is the smaller even integer and x+2 is the next so it will be larger.
The integers are 4 and 6
Step-by-step explanation:
Let the two consecutive even integers be x and x+2
Here x is the smaller even integer and x+2 is the next so it will be larger.
Now according to the given statement
Sum of both: 
difference of 3 times the larger & 2 times the smaller:
Putting the sum and difference equal:
Solving the equation
The next integer will be:
Hence,
In assumption, x is the smaller even integer and x+2 is the next so it will be larger.
The integers are 4 and 6.
