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2 years ago

15

Simplify -(3a-3) it’s hard

1 answer:

Rufina [12.5K]2 years ago

7 0

hi

-(3a-3) = -3a +3

you cannot do much more.

You can rewrite it as 3 ( -a +1) or as -3 ( a -1) but nothing more really.

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Rewrite in simplest terms: -(2c + 8) + 8c

garik1379 [7]

Answer:

$6c-8$

Step-by-step explanation:

We have:

$-(2c+8)+8c=$

$-2c-8+8c=\\$

$6c - 8$

6 0

3 years ago

Graph by using the slope and the y intercept.

Mashutka [201]

1. a) equation of the line :

$y = \dfrac{2}{5}x - 7$

y - intercept = -7

so, it will pass through point (0, -7)

and if we plug the value of x as 5, we get

$y = (\dfrac{2}{5} \times 5) - 7$

$y = 2 - 7$

$= - 5$

so, it will pass through point (5, -5) too

now, just plot the points (0 , -7) and (5 , -5) and join them.

2. b) equation of line is :

$y = - 3x + 5$

here, y - intercept = 5

so the line passes through point (0 , 5)

now, Plugging the value of x = 1 we get :

$y =( - 3 \times 1) + 5$

$y = - 3 + 5$

$y = 2$

so, the given line passes through point (1 , 2)

plotting the points, we can get our required line.

6 0

3 years ago

Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.

Grace [21]

$\dfrac{n^2+n+1}{n-1}=\dfrac{(n-1)^2+3(n-1)+3}{n-1}=n-2+\dfrac3{n-1}$

The remainder term $\dfrac3{n-1}$ will never vanish, and will always be rational as long as the denominator is not 1, 3, or -3.

$n-1=1\implies n=2$
$n-1=3\implies n=4$
$n-1=-3\implies n=-2$

7 0

3 years ago

Line M passes through the point (-5,9) and (-1,9)

natali 33 [55]

The last one is true

Line m is a horizontal line with a slope of 0

good luck

8 0

4 years ago

Read 2 more answers

On a coordinate graph, which of the following is TRUE of Quadrant 3? is it A. The x and y values are both positive. B. The x val

Flura [38]

D is the answer . -JZ

6 0

3 years ago