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2 answers:
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Answer:
1). Mean = 2.275
2). Median = 2 vehicles
Step-by-step explanation:
From the given table,
Number of vehicles (x) Frequency (f) (f)×(x) Cumulative freq.
0 11 0 11
1 52 52 63
2 66 132 129
3 35 105 164
4 19 76 183
5 12 60 195
6 5 30 200
Number of households = 200
Mean =
=
= 2.275
Median = value of observation
= value of observation
= Value of 100.5th observation
= Since 100.5th observation lies in the row of cumulative freq. = 129
= 2
Therefore, median number of registered vehicles per California household
= 2 vehicles
Let's say you want to compute the probability 
where 
converges in distribution to 
, and follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing such that its mean and variance are the same as those for .
Example: If is binomially distributed with 
and 
, then has mean 
and variance 
. So you can approximate a probability in terms of with a probability in terms of :
where
follows the standard normal distribution.
Example: If
where