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3 years ago

29+10j= -11 Find the value for j

Mathematics

2 answers:

Svetllana [295]3 years ago

8 0

29+10j=-11
-29 -29

10j=-40
/10 /10

J=-4

Hope I helped,
-CSX

Nezavi [6.7K]3 years ago

7 0

<span>29+10j= -11
</span><span>29+10j - 29 = -11 - 29 (subtract 29 to both sides)
10j = -40
10j/10 = -40/10 (divide both sides by 10)
j = -4

</span>

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Answer: No, Cammie is not correct. She can mow $1\frac{1}{5}\ acres$ in one hour (See explanation).

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Convert the mixed number to an impoper fraction:

1. Multiply the whole number part by the denominator of the fraction and add the product to the numerator.

2. The denominator does not change.

Then:

$1\frac{1}{4}=\frac{(1*4)+1}{4}=\frac{5}{4}$

Let be "x" the acres Cammie can mow in one hour.

You know that she can mow $\frac{1}{2}\ acre$ in 25 minutes, then you can set up the following proportion (Remember that 1 hour has 60 minutes):

$\frac{\frac{1}{2}}{25}=\frac{x}{60}$

Solving for "x", you get:

$\frac{\frac{1}{2}}{25}=\frac{x}{60}\\\\(60)(\frac{1}{50})=x\\\\x=\frac{6}{5}$

Convert from improper fraction to mixed number:

1. When you divide 6 by 5, the quotient is 1. This will be the whole number part.

2. The remainder is 1. This will be the numerator.

3. The denominator does not change.

Then:

$x=1\frac{1}{5}$

Therefore, she can mow $1\frac{1}{5}\ acres$ in one hour.

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3 years ago

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4 years ago

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3 years ago

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Your answer is 1 8/15

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4 years ago

A history professor decides to give a 12-question true-false quiz. She wants to choose the passing grade such that the probabili

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Answer:

we can set the 9 as a benchmark to be the score for the passing grade so that probability of passing a student who guesses every question is less than 0.10

Step-by-step explanation:

From the given information;

Sample size n = 12

the probability of passing a student who guesses on every question is less than 0.10

In a alternative - response question (true/false) question, the probability of answering a question correctly = 1/2 = 0.5

Let X be the random variable that is represent number of correct answers out of 12.

The X $\sim$ BInomial (12, 0.5)

The probability mass function :

$P(X = k) = \dfrac{n!}{k!(n-k)!} \times p^k\times (1-p)^{n-k}$

$P(X = 12) = \dfrac{12!}{12!(12-12)!} \times 0.5^{12}\times (1-0.5)^{12-12}$

P(X = 12) = 2.44 × 10⁻⁴

$P(X = 11) = \dfrac{12!}{11!(12-11)!} \times 0.5^{11}\times (1-0.5)^{12-11}$

P(X =11 ) = 0.00293

$P(X = 10) = \dfrac{12!}{10!(12-10)!} \times 0.5^{10}\times (1-0.5)^{12-10}$

P(X = 10) = 0.01611

$P(X = 9) = \dfrac{12!}{9!(12-9)!} \times 0.5^{19}\times (1-0.5)^{12-9}$

P(X = 9) = 0.0537

$P(X = 8) = \dfrac{12!}{8!(12-8)!} \times 0.5^{8}\times (1-0.5)^{12-8}$

P(X = 8) = 0.12085

$P(X = 7) = \dfrac{12!}{7!(12-7)!} \times 0.5^{7}\times (1-0.5)^{12-7}$

P(X = 7) = 0.19335

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We can see that,a t P(X = 9) , the probability is 0.0537 which less than 0.10 but starting from P(X = 8) downwards the probability is more than 0.01

As such, we can set the 9 as a benchmark to be the score for the passing grade so that probability of passing a student who guesses every question is less than 0.10

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