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svp [43]
1 year ago
10

a radioactive sample contains 3.00 g of pure 11c, which has a half-life of 20.4 min. (a) how many moles of 11c are present initi

ally?
Mathematics
1 answer:
sveta [45]1 year ago
8 0

The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the number of mole of pure 11C. Detail below:

<h3>How to determine the mole of 11C</h3>

From the question given, the following data were obtained:

  • Molar mass of 11C = 11 g/mol
  • Mass of 11C = 3 g
  • Mole of 11C =?

Mole = mass / molar mass

Mole = 3 / 11

Mole = 0.2727 mole

Therefore, the number of mole of pure 11C initially present is 0.2727 mole

Learn more about mole:

brainly.com/question/13314627

#SPJ4

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Answer:

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Step-by-step explanation:

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We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

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using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

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∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

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9-1=7x-5x

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3 years ago
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nirvana33 [79]

Answer:

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Step-by-step explanation:

A line with zero slope has no dependence on x. It is simply ...

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The constant must be the same as the y-value of the point you want the line to go through. Since the point is (12, -9), the constant is -9 and the equation is ...

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2 years ago
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