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2 years ago

11

The sum of the square roots of any two sides of an isosceles triangle is equal to the to the square root of the remaining side t

rue or false

1 answer:

Galina-37 [17]2 years ago

3 0

Nope- false
The sum of the square roots of two sides of a _right_ triangle is equal to the hypotenuse.

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Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 3 over 4 power, all over 2

Zepler [3.9K]

We are asked in this problem to determine the simplified expression of the statement given. The rules that apply in exponential functions is that when an exponential term is raised to the power of an integer, the simplified term has a degree that is equal to the product of the integers involved. The operations involved should be applicable to terms with the same base number only. In this problem, we thus write:

2^3/4 / 2^1/2 = 2^3/4 * 2^-1/2 = = 2^(3/4 - 1/2) = 2^ 1/4. hence the answer is 2^0.25 or simply equal to 1.1892 determined using a calculator.

6 0

2 years ago

Determine the distance between the following two points. (round to the nearest hundredths)

padilas [110]

Answer:

$d=7.07$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:

$d=\sqrt{(3-(-2))^2+(-4-1)^2}$

$d=\sqrt{(3+2)^2+(-5)^2}$

$d=\sqrt{(5)^2+25}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

$d=7.07$

5 0

2 years ago

A local electronics store raised its prices on headphones by 20%. The headphones that Stan wants to buy now cost $36. How much d

atroni [7]

You would do 36$ -20% =28.8

4 0

3 years ago

A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.

kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

$C = Children; S = Students; A = Adults$

For the capacity, we have:

$C + S + A = 329$

For the tickets sold, we have:

$5C + 7S + 12A = 2388$

Half as many as adults are children implies that:

$A = \frac{C}{2}$

Required

Solve for A, C and S

The equations to solve are:

$C + S + A = 329$ -- (1)

$5C + 7S + 12A = 2388$ -- (2)

$A = \frac{C}{2}$ -- (3)

Make C the subject in (3)

$C = 2A$

Substitute $C = 2A$ in (1) and (2)

$C + S + A = 329$ -- (1)

$2A + S + A = 329$

$3A + S = 329$

Make S the subject

$S = 329 - 3A$

$5C + 7S + 12A = 2388$ -- (2)

$5*2A + 7S + 12A = 2388$

$10A + 7S + 12A = 2388$

$7S + 22A = 2388$

Substitute $S = 329 - 3A$

$7(329 - 3A) + 22A = 2388$

$2303 - 21A + 22A = 2388$

$2303 +A = 2388$

Solve for A

$A = 2388 - 2303$

$A = 85$

Recall that: $C = 2A$

$C = 2 * 85$

$C = 170$

Recall that: $S = 329 - 3A$

$S = 329 - 3 * 85$

$S = 329 - 255$

$S = 74$

Hence, the result is:

$C = 170$

$S = 74$

$A = 85$

8 0

2 years ago

Please help!!<br> Question is in the picture!!

Debora [2.8K]

$\frac{17}{60}$ and $\frac{1}{4}$ are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = $\frac{12}{60}=\frac{1}{5}$

Probability of getting 2 = $\frac{17}{60}$

Probability of getting 3 = $\frac{15}{60}=\frac{1}{4}$

Probability of getting 4 = $\frac{16}{60}=\frac{4}{15}$

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: $\frac{17}{60}$

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: $\frac{1}{4}$

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: $\frac{7}{15}$

This is not obtained above. So, it is not the experimental probability.

Option E: $\frac{12}{43}$

This is not obtained above. So, it is not the experimental probability.

Hence $\frac{17}{60}$ and $\frac{1}{4}$ are the experimental probabilities from the table.

5 0

3 years ago