To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,
Step-by-step explanation:
well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles
Answer:
he gained 900 dollars.
Step-by-step explanation:
Answer:
d. -7/25
Step-by-step explanation:
π<θ<3π/2 in third quadrant
tanθ = 4/3
sinθ = - 4/5
cosθ = - 3/5
cos 2θ = cos²θ - sin²θ = (- 3/5)² - (- 4/5)² = 9/25 - 16/25 = - 7/25
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