Answer:
B. 1.-1,-2
Step-by-step explanation:

Substitute g(x)=0

Move the expression to the left

Factor out -x^2 from the expression

Factor out (x+2) from the expression

When the product of the factor equals 0, at least one factor is 0


Solve for x

9514 1404 393
Answer:
Step-by-step explanation:
If Anna's age is represented by A, then 12 more than Anna's age will be ...
12 + A
Jason's age is said to be 12 more than Anna's age, so ...
J = 12 + A
__
The sum of their ages will be J + A. That is said to be 50, so ...
J + A = 50
_____
These equations can be solved by using the first to substitute for J in the second.
(12 +A) +A = 50
2A = 38 . . . . . . . . subtract 12
A = 19 . . . . . . . . . . divide by 2
J = 12 +19 = 31 . . . find Jason's age
Jason is 31; Anna is 19.
Answer:
a = 3, b = 4, c = 5
Step-by-step explanation:
Assuming we're working with a right triangle, where c is the hypotenuse, then using the definition of the cosine being the adjacent side over the hypotenuse, then we know:
a = 3, because it is the side adjacent to B
b = 4, because it is the side adjacent to A
c = 5, because it is the denominator in bot fractions
This of course assumes that there is no additional ratio in place. For example, if the lengths were instead 8, 6 and 10 respectively, then the cosines given would still be 4/5 and 3/5. Truthfully these only tell relative sizes of the sides, and not their absolute sizes.
Answer:
$221.0665 so $221.07
Step-by-step explanation:
Answer:
1 and 3, 2 and 4.
Step-by-step explanation:
1. -1.66666666667
2. 1
3. -1.66666666667
4. -1