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astraxan [27]
1 year ago
10

Help me on number 10 please.​

Mathematics
2 answers:
wel1 year ago
8 0

Answer: The answer is 32.

Step-by-step explanation:

48 <u>Divided By 3</u><em> Multiplied by 2 = 32 </em>

<em></em>

<em>So the value of N is: 32.</em>

LenaWriter [7]1 year ago
3 0

Answer:

9.) B. division

10.) 8

Explanation:

9. Which operation to do first in order of operations?

Answer: Applying BODMAS where:

[B] brackets

[O] order

[D] division

[M] multiplication

[A] addition

[S] subtraction

Maintaining order, division operation is done first. Then multiplication and then addition and so on.

10. Given that N = 48 ÷ 3 × 2

⇒ N = 48 ÷ 3 × 2

⇒ N = 48 ÷ 6

⇒ N = 8

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(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
Please help me only serious answers ☺️
romanna [79]

Answer:

Parallelogram

Result

Area = b × h

= 5.5 × 11

<h3>= 60.5 feet2</h3>

<h2>60.5 cm²</h2>
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What one should I choose I'm stumped ??
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