Question

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Answer 1

Answer:

$\dfrac{3x+6}{x^2+x-6}$

Step-by-step explanation:

Notice that we can factor the expression $x^2-x-2$ as $(x-2)(x+1)$. Similarly, we can express $3x+3$ as $3(x+1)$. Now, we can multiply the fraction together as $\dfrac{(x+2)(3)(x+1)}{(x-2)(x+1)(x+3)} = \dfrac{3(x+2)}{(x-2)(x+3)} = \boxed{\dfrac{3x+6}{x^2+x-6}}$.