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Dmitry [639]
1 year ago
12

Lower range tones generally require ________ speakers. lower range tones generally require ________ speakers. multiple choice

Computers and Technology
1 answer:
lilavasa [31]1 year ago
6 0

Lower range tones generally require larger speakers.

It's no secret that lower range tones generally require larger speakers. This is because lower frequencies have longer wavelengths, and thus require more physical space to produce.

While this may seem like a simple concept, there are a few things to keep in mind when it comes to speaker size and low frequency response. First, larger speakers can usually reproduce lower frequencies more efficiently than smaller ones. Second, the size of the speaker's enclosure also plays a role in how well it can reproduce low frequencies.

A larger enclosure will typically have an easier time reproducing low frequencies than a smaller one.

Keep these things in mind when selecting speakers for your system. If you're looking for accurate low frequency reproduction, make sure to choose speakers with larger drivers and enclosures.

Learn more on speakers here:

brainly.com/question/14649463

#SPJ4

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2. An evil twin attack that broadcasts a legitimate SSID for an unauthorized network is an example of what category of threat? A
avanturin [10]

Answer:

A. Spoofing

Explanation:

Spoofing is the act of disguising a communication from an unknown source as being from a known, trusted source. Spoofing can apply to emails, phone calls, and websites, or can be more technical, such as a computer spoofing an IP address, Address Resolution Protocol (ARP), or Domain Name System (DNS) server.

IP spoofing involves an attacker trying to gain unauthorised access to a system by sending messages with a fake or "spoofed" IP address to make it look like the message came from a trusted source, such as one on the same internal computer network, for example.

Email spoofing often involves things like requests for personal data or financial transactions. The emails appear to be from trusted senders such as customers, coworkers, or managers but they are actually from cyber criminals who deliberately disguise themselves to gain your trust and your help with the action they want you to take

7 0
4 years ago
If you created a variable called name, what data type would that value be? Group of answer choices a float a string a Boolean an
Semenov [28]

I think its an integer

8 0
3 years ago
Read 2 more answers
•Should other states wait to see if the high-speed rail system works well before starting their own plans for similar systems?
solmaris [256]
Other states should see how well the system works and also understand how much money it requires for the state to build a high-speed rail system.
7 0
3 years ago
You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting).
Travka [436]

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If \frac{2}{3} of a page occupies 1 kB of memory, we can calculate how much memory a book will take

2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.

8 0
4 years ago
Assume that an int variable counter has already been declared. Assume further a variable counterPointer of type "pointer to int"
Triss [41]

Answer:

Following are the statement:

counterPointer = &counter;

Explanation:

The following statement is correct because in the question it is given that there is an integer data type variable i.e., "counter" and there is another integer data type pointer variable i.e., "counterPointer" and finally we write a statement in which the pointer variable points to the integer variable.

5 0
3 years ago
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