3 years ago

The expression \sqrt[3]{3}\cdot \sqrt[5]{3^6}

Mathematics

1 answer:

Norma-Jean [14]3 years ago

3 0

3/6 because I got it right on the quiz and it was easy txt me if you need help

You might be interested in

How to find the asymtope of a function

Darya [45]

Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.

3 0

3 years ago

K=6x+10, solve for k

kicyunya [14]

Answer:

x=(10-k)÷6

Step-by-step explanation:

6x=10-k

x=(10-k)÷6

4 0

3 years ago

Please help please please

Grace [21]

$\Omega=\{1;\ 2;\ 3;\ 4;\ 5;\ 6;\ 7;\ 8;\ 9;\ 10\}\\\\|\Omega|=10\\\\A=\{1;\ 3;\ 6;\ 7\};\ B=\{2;\ 3\}\\\\A\ \cup\ B=\{1;\ 2;\ 3;\ 6;\ 7\}\\\\|A\ \cup\ B|=5\\\\P(A\ \cup\ B)=\dfrac{|A\ \cup\ B|}{|\Omega|}\to P(A\ \cup\ B)=\dfrac{5}{10}=\dfrac{1}{2}=0.5=0.50$