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IgorLugansk [536]
3 years ago
9

I am desperate and so clueless. Expertise please! Select EACH correct answer.

Mathematics
1 answer:
Sedaia [141]3 years ago
7 0
K(x) = (1/4)^x

(1,4) when x = 1, k(1) = (1/4)^1 = 1/4....FALSE
(3, 1/64) when x = 3, k(3) = (1/4)^3 = 1/64....TRUE
(-1,4) when x = -1, k(-1) = (1/4)^-1 = 4....TRUE
(0, 1/4) when x = 0, k(0) = (1/4)^0 = 1....FALSE

answer
(3, 1/64)
(-1,4)



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Please help!
postnew [5]
Lets solve the equation first:
<span> 0.5 – |x – 12| = –0.25
</span>= 1/2 - |x - 12| = -1/4
= 2 - 4<span>|x - 12| = -1
= 4|x - 12| = 3
= |x - 12| = 0.75
positive case, x >= 12
x - 12 = 0.75
x = 12.75
negative case, x < 12
x - 12 = -0.75
x = 11.25
So those are the two solutions.
These apply:
</span>1.) The equation will have no solutions.
2.) A good first step for solving the equation is to subtract 0.5 from both sides of the equation.
<span>3.) A good first step for solving the equation is to split it into a positive case and a negative case.
</span><span>5.) The negative case of this equation is x – 12 = –0.75.</span>
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