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1 year ago

Find the perimeter of △ABC with vertices A(−5, 3), B(4, −5), and C(−5, −5). Round your answer to the nearest hundredth.

Mathematics

1 answer:

sertanlavr [38]1 year ago

8 0

The perimeter of △ABC with vertices A(−5, 3), B(4, −5), and C(−5, −5) is 29.04 units

<h3>Perimeter of a triangle</h3>

The perimeter of a triangle is the sum of the sides of the triangle.

Given the coordinate points A(−5, 3), B(4, −5), and C(−5, −5)

Determine the distance AB, AC and BC using the distance formula

AB = √(-5-3)²+(4+5)²

AB = √64+81
AB = √145

AB = 12.04 units

AC = √(-5-3)²+(-5+5)²

AC = √64

AC = 8 units

BC = √(-5-4)²+(-5+5)²

BC = √81
BC = 9 units

Take the sum

Perimeter of triangle ABC = 9 + 8 + 12.04

Perimeter of triangle ABC = 29.04 units

Hence the perimeter of △ABC with vertices A(−5, 3), B(4, −5), and C(−5, −5) is 29.04 units

Learn more on perimeter of triangle here: brainly.com/question/24382052

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