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ANEK [815]
3 years ago
11

What is the radius of a circle whose equation is x2 + (y – 8)2 = 25?

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0
The formula for a circle is (x - h)^2 + (y - k)^2 = r^2
Where (h, k) is the center and r is the radius.
x^2 + (y - 8)^2 = 25
25 = r^2
So the radius is sqrt 25 or 5.
Radius = 5
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<h2>Answer:</h2>10.\text{ Option B is correct}

<h2>Explanation:</h2>

Given the equation expressed as:

2x+5=8x

First, we need to calculate the value of "x" from the given expression.

Step 1: Given the equation 2x + 5 = 8x

Step 2: Subtract 5 from both sides:

\begin{gathered} 2x+5-5=8x-5 \\ 2x+\cancel{5}-\cancel{5}=8x-5 \\ 2x=8x-5 \end{gathered}

Step 3: Subtract 8x from both sides

\begin{gathered} 2x-8x=8x-8x-5 \\ -6x=\cancel{8x}-\cancel{8x}-5 \\ -6x=-5 \end{gathered}

Step 4: Divide both sides by -6

\begin{gathered} \frac{-6x}{-6}=\frac{-5}{-6} \\ x=\frac{5}{6} \end{gathered}

Step 5: Get the value of 12x. Substitute x = 5/6 into the expression to have:

\begin{gathered} 12x=12(\frac{5}{6}) \\ 12x=\cancel{12}^2(\frac{5}{\cancel{6}^1}) \\ 12x=2\times5 \\ 12x=10 \end{gathered}

Therefore the value of 12x is 10

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