Answer:
by substituting the values we get
51÷(15+2)
51÷17=3
hope it helps you mate
please mark me as brainliast
Notice the picture below
the lateral area, or just the area of the sides, well, the sides are really just 4 triangles, so just get the area of each, and sum them up, that's the lateral area
See diagram
I wrote that the degrees are 70 each because it is isocolese and 140/2=70
a.
to solve for the diagonal, I'm going to use trig to find the height and the base then use pythagorean theorem to find the diagonal
so
see I've drawn an auxiliry line to make a right triangle on the leftmost side
so
we want to find the height and base
sin(70°)=h/7
so 7sin(70°)=h≈6.57785
cos(70°)=base/7
so 7cos(70°)=base≈2.39414
now
the entire long base is 22, so that big triangle with the diagonal as the hyptonuse is 22-2.39414=19.6059
use pythagorean theorem, like 6.57785²+19.6059²=diagonal²
we get that the diagonal is about 20.68ft
b.
we got that the base was 7cos(70°)
2 of those bases so 22-14cos(70°)=17.2117ft or rounded 17.21ft
a. 20.68ft
b. 17.21ft
The total distance between the two women would simply be
the sum of the hypotenuse formed by the triangular path they created.
For each women:
<span>c^2 = a^2 + b^2</span>
c^2 = 3^2 + 4^2
c^2 = 9 + 16
c^2 = 25
c = 5 m
Therefore the distance between the two is:
distance between the two women = 2 * c
<span>distance between the two women = 10 m</span>
Hello you answer will be...... -x+4
let me know if I’m right