All categories

3 years ago

How many garbage cans should be placed in each campground? Explain how you can use addition or multiplication to find the answer

Mathematics

1 answer:

Vikentia [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Multiplication

Ratio of Tables to garbage = 8:3

Small camp ground:

40 picnic tables and let x be the number of garbage cans

$\frac{8}{3}=\frac{40}{x}\\\\\frac{8*5}{3*5}=\frac{40}{x}\\\\\frac{40}{15}=\frac{40}{x}\\\\$

x = 15

Small campground with 40 picnic table needs 15 garbage cans

Large picnic ground:

120 picnic tables and let y be the number of garbage cans

$\frac{8}{3}=\frac{120}{y}\\\\\frac{8*15}{3*15}=\frac{120}{y}\\\\\frac{120}{45}=\frac{120}{y}$

y= 45

Big campground with 120 picnic table needs 45 garbage cans

You might be interested in

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 44 o

Cerrena [4.2K]

Answer:

a) No 95% of values will fall between (24;64); 68,27% will fall between (34;54)

b)71,83 % will fall between 34 and 64 ounces

Step-by-step explanation:

Empirical rule establishes, for a normal distribution with mean μ and σ as standard deviation:

In interval μ ± σ or ( μ + σ ; μ - σ) we should find 68.27 % of all values of the population, and by simmetry 68.27/2 = 34,14 % should be over the mean and the other half would be values below the mean

Therefore in our case

μ + σ = 44 + 10 = 54

And

μ - σ = 44 - 10 = 34

a) Then 68,34 % of values will fall in this interval

We know now that value 34 is 1* σ below the mean, and is at the limit of 34,14 %

b) μ + 2*σ = 44 * 2*10 = 44 + 20 = 64

64 is the upper limit for the interval μ + 2*σ and we know that 95.45 % of all values will fall between ( μ - 2*σ ; μ + 2*σ ) and by simmetry just one side of this interval (the right side ) will have 95.45/2 = 47;73 %

Then in interval going from ( 34 ; 64 ) we shoud find 47.73 + 34,14

71,83 % of all values will fall between 34 and 64

7 0

4 years ago

Help !

aivan3 [116]

Answer:

a. p(orange) = 5/14

b. p(green) = 3/14

c. p(red) = 1/7

d. p(brown) = 2/7

e. p(brown or red) = 3/7

Step-by-step explanation:

1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.

p(color) = (number of pencils of that color)/(total number of pencils)

p(color) = (number of pencils of that color)/14

a. If a pencil is picked at random, what is the probability that the pencil

will be orange?

p(orange) = 5/14

b. If a pencil is picked at random, what is the probability that the pencil

will be green?

p(green) = 3/14

c. If a pencil is picked at random, what is the probability that the pencil will be red?

p(red) = 2/14 = 1/7

d. If a pencil is picked at random, what is the probability that the pencil

will be brown?

p(brown) = 4/14 = 2/7

e. If a pencil is picked at random, what is the probability that the pencil

will be brown or red?

brown: 4

red: 2

brown or red: 4 + 2

p(brown or red) = 6/14 = 3/7

3 0

3 years ago

What is 1/4 of 1/2 of a pizza?

jenyasd209 [6]

1/4 of 1/2 of a pizza is an 1/8 of a pizza.

(1/4)*(1/2)=1/8

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to cot t sec t?

Solnce55 [7]

Answer: $csc(t)$

Step-by-step explanation:

Alright, lets get started.

The given expression is given as :

$cot( t) \times sec (t)$

We know quotient identity as :

$cot(t)=\frac{cos(t)}{sin(t)}$

Similarly, we know reciprocal identity as :

$sec(t)=\frac{1}{cos(t)}$

lets plug the value of cot and sec in given expression

$\frac{cos(t)}{sin(t)} \times \frac{1}{cos(t)}$

cos will be cancelled, remaining will be

$\frac{1}{sin(t)}$

Using reciprocal identity again, that will equal to :

$csc(t)$ ................... Answer (A)

8 0

3 years ago

A store sells a 33-pound bag of oranges for \$ 3.60$3.60 and a 55-pound bag of oranges for \$ 5.25$5.25. What is the difference

katrin [286]

Answer:

0.01364

Step-by-step explanation:

It is given that,

A store sells a 33-pound bag of oranges for $3.60 and a 55-pound bag of oranges for $5.25.

Price per pound of 33 pound bag is 3.60/33 = 0.10909 price per pound

Price per pound of 55 pound bag of oranges is 5.25/55 = 0.09545 price per pound

Difference between price per pound for the 33-pound bag of oranges and the price per pound for the 55-pound bag of oranges is :

D = 0.10909 - 0.09545

D = 0.01364

Therefore, this is the required solution.

3 0

3 years ago