Step-by-step explanation:
1)
Let x=larger number
y=smaller number
x+y=59
x-y=13
Now adding these two equations we get
2x=72
x=36
Now as x-y=13
y=x-13=36-13=23
y=23
Therefore the larger number is 36 and the smaller number is 23
(or else u could also write)
The numbers are 36 and 23
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2)
Let x=first number
y=Second number
x+y=15
2x-y=6
Now adding these two equations we get
3x=21
x=7
Now as x+y=15,
y=15-x=15-7=8
y=8
Therefore the first number is 7 and the second number is 8
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3)
Let x=Larger number
y=smaller number
x-y=3
x-3y=-11
Now on subtracting these two equations we get
2y=14
y=7
Now as x-y=3,
x=y+3=7+3=10
x=10
Therefore the larger number is 10 and the smaller number is 7
You will need to find the lowest common multiple.
6 = 2 x 3
20 = 2 x 2 x 5
LCM = 2 x 2 x 3 x 5 = 60
The 60th visitor will be the first to get both.
Answer:
x=7
Step-by-step explanation:
ln x +ln(x+1)=ln 56
ln x(x+1)=ln 56
so x(x+1)=56
x^2+x-56=0
(x+8)(x-7)=0
x= -8 or x=7
and lnx,x>0
so x=7
please refer to this image
please don't report this answer if it is wrong
but if its correct so please mark me as brainlist
You can not use either of them because neither of them have a variable= to the eqaution
ex.) y= 3x+25
