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faust18 [17]
1 year ago
5

Solve the inequality and express your answer in interval notation. x² + 8x + 3 < 0

Mathematics
1 answer:
sattari [20]1 year ago
3 0

<u><em>Solution:</em></u>

A.) (-4-\sqrt{13},-4+\sqrt{13})

Hope this helps!

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Someone help with these its due tomorrow. Ahhhh
Oksana_A [137]
I'll help with 1.) 
9m:3m = 6m:x
cross multiply
9x=3*6
9x=18
divide both sides 9
x = 2
the missing side is 2m

The missing angle is 30°

Question 2.)
find the ratios to solve for missing side
24:6 = b:4
cross multiply
24*4 = 6b
96 = 6b
divide both sides by 6
16 = b

The missing angle is 32°

Question 3.)
Find missing side d
make a ratio
5:d = 3:9
cross multiply
5*9 = 3d
45 = 3d 
divide both sides by 3
15 = d

the missing angle is 90°

Question 4.)
Find missing side s
write as proportion or ratio
36:6 = s:2
cross multiply
36*2 = 6s
72 = 6s
divide both sides by 6
s = 12

The missing angle t is 71°

Hope this helps :)
4 0
3 years ago
Write 585% as a decimal and as a fraction.
Pepsi [2]
Let's start by turning it into a decimal.
- to turn any percent into a decimal you move the decimal point two places to the left.
Decimal= 5.85

To turn into fraction you know 5 is the whole number and you have 85 hundredths. Just put that in fraction form.
5 and 85/100
Now simplify by dividing both by 5
Answer is
5 and 17/20


3 0
3 years ago
Consider the quadratic function:
sdas [7]

Answer:

Step-by-step explanation:

I'm not sure how you are finding this in class, but the easiest way by far is to use the expressions for h and k:

h=\frac{-b}{2a}  and

k=c-\frac{b^2}{4a}

(Just a fun fact:  Those expressions come from the quadratic formula that help us to factor a quadratic equation.)

Filling in for h:

h=\frac{-(-8)}{2(1)}  simplifies to

h = \frac{8}{2}=4

Filling in for k:

k=-9-\frac{(-8)^2}{4(1)}  which simplifies a bit to

k=-9-\frac{64}{4}  which simplifies a bit more to

k=-9-16=-25

The vertex, then, is (4, -25).

You would also find this if you completed the square.  But again, I'm not sure how you're solving for the vertex in class.

8 0
3 years ago
A tank contains 120 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
gtnhenbr [62]

If A(t) is the amount of salt in the tank at time t, then A(0) = 50 g and

A'(t) = (1 g/L)*(3 L/min) - (A(t)/120 g/L)*(3 L/min)

\implies A'+\dfrac A{40}=3

Multiply both sides by e^{t/40}, so that the left side can be condensed as the derivative of a product:

e^{t/40}A'+\dfrac{e^{t/40}}{40}A=3e^{t/40}

\left(e^{t/40}A\right)'=3e^{t/40}

Integrate both sides and solve for A(t).

e^{t/40}A=120e^{t/40}+C

\implies A(t)=120+Ce^{-t/40}

Given that A(0) = 50 g, we have

50=120+C\implies C=-70

so that the amount of salt in the tank at time t is

\boxed{A(t)=120-70e^{-t/40}}

7 0
3 years ago
3. Multiply (-7)(2)(-2). (5 points)<br> 1. -28<br> 2. -14<br> 3. 28<br> 4. 14
Rashid [163]

Answer:

28

Step-by-step explanation:

-7x2 is -14

-14x-2 is positive 28.

5 0
3 years ago
Read 2 more answers
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