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faust18 [17]
2 years ago
5

Solve the inequality and express your answer in interval notation. x² + 8x + 3 < 0

Mathematics
1 answer:
sattari [20]2 years ago
3 0

<u><em>Solution:</em></u>

A.) (-4-\sqrt{13},-4+\sqrt{13})

Hope this helps!

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Question in picture below
Artyom0805 [142]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the slope of the line that contains the following points. r(-2, 4), s(6, -2)
tangare [24]

Finding the slope using two points:

The formula for slope is

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

In this case...

y_{2} =-2\\y_{1} =4\\x_{2} =6\\x_{1} =-2

^^^Plug these numbers into the formula for slope...

\frac{-2 - 4}{6 - (-2)}

\frac{-6}{8}

^^^Can be further simplified to...

\frac{-3}{4}

^^^This is your slope

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
3 years ago
Read 2 more answers
Rachel has 15 markers. She gives 4 markers to
MA_775_DIABLO [31]

The answer is 8 markers

Step-by-step explanation:

Since all children are collecting markers from Rachel who has 15 markers, the equation will be:

Markers Left = 15 - 4- 3

Markers Left = 11 - 3

Markers Left = 8

7 0
2 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

3 0
3 years ago
Please help asap and please no links or answering just for points!! I’m already stressed :(
masha68 [24]

Answer:

let the number be x

wo a/q we have,

4x + 5 = 7

hope this answer helps you dear! take care

4 0
3 years ago
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